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Chapter 6: Q27E (page 1274)

A proton has momentum with magnitude p0 when its speed is 0.400c. In terms of p0, what is the magnitude of the proton鈥檚 momentum when its speed is doubled to 0.800c?

Short Answer

Expert verified

P=3.055P0

Step by step solution

01

Step 1:Formula of relativistic momentum.

P=mv1-v2/c2=纬尘惫

Where

P鈫�momentum纬鈫�lorentzfactorm鈫�restmassv鈫�velocity

02

Step 2:Calculating the magnitude of proton’s momentum.

Using the formula for relativistic momentum,

P1=mv11-v12/c2P1=mv11-v02/c2P1P0=v11-v12/c2*1-v02/c2v0=1-v02/c21-v12/c2*0.8000.400=3.055P1=3.055P0

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