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Electrostatic precipitators use electric forces to remove pollutant particles from smoke, in particular in the smokestacks of coal颅 burning power plants. One form of precipitator consists of a vertical, hollow, metal cylinder with a thin wire, insulated from the cylinder, running along its axis (Fig. P23.65). A large potential difference is established between the wire and the outer cylinder, with the wire at lower potential. This sets up a strong radial electric field directed inward. The field produces a region of ionized air near the wire. Smoke enters the precipitator at the bottom, ash and dust in it pick up electrons, and the charged pollutants are accelerated toward the outer cylinder wall by the electric field. Suppose the radius of the central wire is 90.0m, the radius of the cylinder is 14.0 cm, and a potential difference of 50.0 kV is established between the wire and the cylinder. Also assume that the wire and cylinder are both very long in comparison to the cylinder radius, so the results of Problem 23.61 apply. (a) What is the magnitude of the electric field midway between the wire and the cylinder wall? (b) What magnitude of charge must a 30.0-g ash particle have if the electric field computed in part (a) is to exert a force ten times the weight of the particle?

Step by step solution

01

Step 1:

Given values:

02

Step 2:

(a) Electric field is given as

Putting the values

Hence, the magnitude of the electric field is .

03

Step 3:

(b) As the electric force is 10 times the weight

So, the charge is given as

Putting the values,

Therefore, the magnitude of charge is.

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