/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q5DQ When is a 1.5 - VAAA battery not... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 4: Q5DQ (page 840)

When is a 1.5 - VAAA battery not actually a 1.5 - V battery? That is, when do this its terminals provide a potential difference of less than 1.5 V ?

Short Answer

Expert verified

The battery emf is less than 1.5 V when the power drop ofiR is there in the battery.

Step by step solution

01

Definition of Potential difference

The potential difference is defined as the work required to move the charge of unit magnitude from a point in the conductor to the other point.

02

Determine the when potential difference provide less than 1.5 - V .

Consider the expression for the voltage.

V=蔚-iR

Here, the voltage is the V, the emf of the battery is 蔚, the current is i and the resistance is R.

Here, the product of the current and the resistance are the voltage drop in the circuit and the V is the voltage available at the terminal. So the actual voltage supplied before the drops is 蔚.

Therefore, the battery emf is less than 1.5 V when the power drop of iRis there in the battery.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A fuse is a device designed to break a circuit, usually by melting when the current exceeds a certain value. What characteristics should the material of the fuse have?

BIO Transmission of Nerve Impulses. Nerve cells transmit electric

signals through their long tubular axons. These signals propagate due to a

sudden rush of Na+ions, each with charge +e, into the axon. Measurements

have revealed that typically about 5.6脳1011Na+ions enter each meter of the

axon during a time of . What is the current during this inflow of charge

in a meter of axon?

In the circuit shown in Fig. E25.30, the 16.0-V battery is removed and reinserted with the opposite polarity, so that its negative terminal is now next to point a. Find (a) the current in the circuit (magnitude anddirection); (b) the terminal voltage Vbaof the 16.0-V battery; (c) the potential difference Vacof point awith respect to point c. (d) Graph the potential rises and drops in this circuit (see Fig. 25.20).

Copper has 8.5脳1022free electrons per cubic meter. A 71.0-cm

length of 12-gauge copper wire that is 2.05 mm in diameter carries 4.85 A of

current. (a) How much time does it take for an electron to travel the length

of the wire? (b) Repeat part (a) for 6-gauge copper wire (diameter 4.12 mm)

of the same length that carries the same current. (c) Generally speaking,

how does changing the diameter of a wire that carries a given amount of

current affect the drift velocity of the electrons in the wire?

A circular area with a radius of6.50cmlies in the xy-plane. What is the magnitude of the magnetic flux through this circle due to a uniform magnetic fieldlocalid="1655727900569" B鈫�=0.230T(a) in the direction of +z direction; (b) at an angle of53.1掳from the direction; (c) in the direction?
See all solutions

Recommended explanations on Physics Textbooks

Thermodynamics

Read Explanation

Wave Optics

Read Explanation

Radiation

Read Explanation

Engineering Physics

Read Explanation

Force

Read Explanation

Famous Physicists

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.