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A plastic circular loop has radius R, and a positive charge q is distributed uniformly around the circumference of the loop. The loop is then rotated around its central axis, perpendicular to the plane of the loop, with angular speed v. If the loop is in a region where there is a uniform magnetic field Bdirected parallel to the plane of the loop, calculate the magnitude of the magnetic torque on the loop.

Short Answer

Expert verified

The magnitude of the magnetic torque on the loop is=12辩蝇谤2B.

Step by step solution

01

Definition of magnetic field

The term magnetic field may be defined as the area around the magnet behave like a magnet.

02

Determine the magnitude of the magnetic torque on the loop.

The moving charged loop create current, so loop treated as circular wire where current I moving through it and the T be the period of the rotation. Than

l=qT

But

f=1T

So

l = qf

And

=2蟿蟿蹿

So

l=q蝇2蟿蟿

Due to magnetic field the torque acting on the loop is =渭叠蝉颈苍

is the angle between magnetic field and magnetic moment which is=90

And

=lA

So

=IAB

ButA=蟿蟿搁2

So

T=q蝇2蟺搁2BT=q蝇R2BT=12辩蝇谤2B


Hence, the magnitude of the magnetic torque on the loop is =12辩蝇谤2B.

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