91Ó°ÊÓ

Use the formula of current

$I=\frac{\mathrm{Î\mu }}{R+r}$

Substitute the given values

$$\begin{gathered} I=\frac{14000V}{10000\mathrm{Î\copyright }+2000\mathrm{Î\copyright }} \\ I=1.17A \end{gathered}$$

Therefore, If the internal resistance of the power supply is $2000\mathrm{Î\copyright }$, the current through the person’s body is 1.17 A

Use the formula of power in relation with current and resistance

$P=I^{2}R$

Substitute the values

$$\begin{gathered} P={\left(1.17A\right)}^2\left(10000\mathrm{Î\copyright }\right) \\ P=13.7kW \end{gathered}$$

Therefore, the power dissipated through the person’s body is$13.7kW$

Use the formula of current used above and transform it accordingly

$r=\frac{\mathrm{Î\mu }-IR}{I}$

Substitute the values

$$\begin{gathered} r=\frac{14000V-\left(0.001A\right)\left(10000\mathrm{Î\copyright }\right)}{0.001A} \\ r=14M\mathrm{Î\copyright } \end{gathered}$$

Therefore, the internal resistance should be $14M\mathrm{Î\copyright }$for the maximum current in the above situation to be 1.00 mA or less