/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q29E A 150-V battery is connected acr... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 4: Q29E (page 913)

A 150-V battery is connected across two parallel metal plates of area 28.5 cm2 and separation 8.20 mm. A beam of alpha particles (charge +2e, mass 6.64 * 10-27 kg) is accelerated from rest through a potential difference of 1.75 kV and enters the region between the plates perpendicular to the electric field, as shown in Fig. E27.29. What magnitude and direction of magnetic field are needed so that the alpha particles emerge undeflected from between the plates?

Short Answer

Expert verified

The magnitude 0.0445T and the direction out of the pageis needed to that alpha particle emerge undeflected from between the plates.

Step by step solution

01

Potential energy and kinetic energy of a charged particle in an electric field

The potential energy and the kinetic energy are equal

Therefore,

12mv2=qV

And

v=2qVm

02

Determine the magnitude and direction of the particle

The potential energy and the kinetic energy are equal

12mv2=qVv=2qVm

Therefore,

v=2qVm=4(1.60脳10鈭�19C)(1750V)6.64脳10鈭�27kg=4.11脳105m/s

And the magnetic force is equal to the electric force

Therefore,

qvB=qEB=Ev

And the electric field is

E=Ed=150V0.00820m=18300V/m

And the magnetic field is

B=EV=18300V/m4.11脳105m/s=0.0445T

Therefore, And the direction of the magnetic field is out of the page and the magnitude is 0.0445T

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A 5.00-A current runs through a 12-gauge copper wire (diameter

2.05 mm) and through a light bulb. Copper has8.5脳108free electrons per

cubic meter. (a) How many electrons pass through the light bulb each

second? (b) What is the current density in the wire? (c) At what speed does

a typical electron pass by any given point in the wire? (d) If you were to use

wire of twice the diameter, which of the above answers would change?

Would they increase or decrease?

The power rating of a light bulb (such as a 100-W bulb) is the power it dissipates when connected across a 120-V potential difference. What is the resistance of (a) a 100-W bulb and (b) a 60-W bulb? (c) How much current does each bulb draw in normal use?

A 1500-W electric heater is plugged into the outlet of a 120-V circuit that has a 20-A circuit breaker. You plug an electric hair dryer into the same outlet. The hair dryer has power settings of 600 W, 900 W, 1200 W, and 1500 W. You start with the hair dryer on the 600-W setting and increase the power setting until the circuit breaker trips. What power setting caused the breaker to trip?

An electron experiences a magnetic force of magnitude4.60脳10-15Nwhen moving at an angle of 60.0掳 with respect toa magnetic field of magnitude3.50脳10-3T. Find the speed ofthe electron.

You connect a battery, resistor, and capacitor as in Fig. 26.20a, where R = 12.0 鈩� and C = 5.00 x 10-6 F. The switch S is closed at t = 0. When the current in the circuit has a magnitude of 3.00 A, the charge on the capacitor is 40.0 x 10-6 C. (a) What is the emf of the battery? (b) At what time t after the switch is closed is the charge on the capacitor equal to 40.0 x 10-6 C? (c) When the current has magnitude 3.00 A, at what rate is energy being (i) stored in the capacitor, (ii) supplied by the battery
See all solutions

Recommended explanations on Physics Textbooks

Magnetism

Read Explanation

Translational Dynamics

Read Explanation

Radiation

Read Explanation

Atoms and Radioactivity

Read Explanation

Rotational Dynamics

Read Explanation

Fields in Physics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.