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Chapter 4: Q5E (page 912)

An electron experiences a magnetic force of magnitude4.60脳10-15Nwhen moving at an angle of 60.0掳 with respect toa magnetic field of magnitude3.50脳10-3T. Find the speed ofthe electron.

Short Answer

Expert verified

The velocity isv鈬赌=9.49脳106m/s

Step by step solution

01

The significance of the magnetic field

The magnetic field force is given by
FB=q(v脳B)F=辩惫叠蝉颈苍胃

Where q is the charge of the particle, V is the velocity and B is the magnetic field

02

Determination of the speed of the electron

We know that the magnetic field force is given by

F=q(v脳B)F=qvBsin胃

Rearranging we get

VFqBsin胃

Plug the values

V=4.60脳10-15N1.6脳10-19C3.50脳10-3Tsin60v=9.496m/sHence,thevelocityisv鈬赌=9.49脳106m/s

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