/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q13E Radio station WCCO in Minneapoli... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Radio station WCCO in Minneapolis broadcasts at a frequency of . At a point some distance from the transmitter, the magnetic-field amplitude of the electromagnetic wave from WCCO is 4.82×10-11T. Calculate (a) the wavelength; (b) the wave number; (c) the angular frequency; (d) the electric-field amplitude.

Short Answer

Expert verified
  1. The wavelength of the electromagnetic wave is 361 m
  2. The wave number of the electromagnetic wave is 174×10-4rad/m.
  3. The angular velocity of the electromagnetic wave is 5.22×106rad/s.
  4. The amplitude of electric field is 144×10-4V/m.

Step by step solution

01

Step 1: Define frequency and write formulas.

The number of waves that moves a fixed point in unit time is known as frequency.

f=1TorÓ¬2Ï€

Where, T = Time period in seconds and is angular frequency in .

The frequency, wavelength, and speed of light of any wave are related by the wavelength-frequency relationship.

The wavelength-frequency relationship is:

c=λf

Where, c is the speed of light which is equal to 3×108m/s, λis the wavelength and is the frequency.

The wavelength is inversely proportional to the frequency.

λ=cforvf

Where, v is velocity of wave in m/s.

The relation between wave number and wavelength is:

k=2πλ

Where, k is wavenumber in rad/m.

The formula used to determine the amplitude of electric and magnetic fields of the wave are:

Emax=2lε0CBmax=Emaxc

02

Determine the wavelength and wave number of wave.

Given that,f=830×103Hz

The wavelength of wave is:

λ=cf=3×108830×103=361m

The wave number of wave is:

role="math" k=2πλ=2π361=174×10-4rad/s

Hence, wavelength of the electromagnetic wave is 361 m and the wave number of the electromagnetic wave is 174×10-4rad/m.

03

Determine the angular frequency and amplitude of electric field.

The angular frequency of wave is:

Ó¬=2Ï€´Ú=2Ï€830×103=5.22×108rad/s

Given that,Bmax=4.82×10-11T

The formula used to determine the amplitude of electric field of the wave is:

Emax=cBmax=3×1084.82×10-11=144×10-4V/m

Hence, the angular velocity of the electromagnetic wave is 5.22×106rad/sand the amplitude of electric field is144×10-4V/m .

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A fuse is a device designed to break a circuit, usually by melting when the current exceeds a certain value. What characteristics should the material of the fuse have?

Suppose a resistor R lies alongeach edge of a cube (12 resistors in all)with connections at the corners. Find theequivalent resistance between two diagonally opposite corners of the cube (pointsa and b in Fig. P26.84).

Electrons in an electric circuit pass through a resistor. The wire on either side of the resistor has the same diameter.(a) How does the drift speed of the electrons before entering the resistor compare to the speed after leaving the resistor? (b) How does the potential energy for an electron before entering the resistor compare to the potential energy after leaving the resistor? Explain your reasoning.

A heart defibrillator is used to enable the heart to start beating if it has stopped. This is done by passing a large current of12Athrough the body at25Vfor a very short time, usually3.0msabout . (a) What power does the defibrillator deliver to the body, and (b) how much energy is transferred ?

You connect a battery, resistor, and capacitor as in Fig. 26.20a, where R = 12.0 Ω and C = 5.00 x 10-6 F. The switch S is closed at t = 0. When the current in the circuit has a magnitude of 3.00 A, the charge on the capacitor is 40.0 x 10-6 C. (a) What is the emf of the battery? (b) At what time t after the switch is closed is the charge on the capacitor equal to 40.0 x 10-6 C? (c) When the current has magnitude 3.00 A, at what rate is energy being (i) stored in the capacitor, (ii) supplied by the battery

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.