/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 63 The block of ice (temperature \(... [FREE SOLUTION] | 91Ó°ÊÓ

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The block of ice (temperature \(0^{\circ} \mathrm{C}\) ) shown in Figure \(\mathrm{P} 9.63\) is drawn over a level surface lubricated by a layer of water \(0.10 \mathrm{~mm}\) thick. Determine the magnitude of the force \(\vec{F}\) needed to pull the block with a constant speed of \(0.50 \mathrm{~m} / \mathrm{s}\). At \(0^{\circ} \mathrm{C}\), the viscosity of water has the value \(\eta=1.79 \times 10^{-3} \mathrm{~N} \cdot \mathrm{s} / \mathrm{m}^{2}\)

Short Answer

Expert verified
The pulling force \(F\) can be calculated as \(F = A \times 8.955 N\), where \(A\) is the contact area of the ice block with the water layer.

Step by step solution

01

Identify relevant information and equation

The problem gives us the thickness of the water layer \(d = 0.10 \, mm\), the speed \(v = 0.50 \, m/s\) at which the ice block is pulled and the coefficient of viscosity \(\eta = 1.79 \times 10^{-3} \, N \cdot s/m^{2}\). We want to find out the force \(F\). The equation for viscous force is given by Stoke's Law where \(F = \eta Av/d\)
02

Conversion to standard units

Convert the layer of water into meters. \(1mm = 0.001m \), so \(d = 0.10 \times 0.001 = 0.0001 m\).
03

Calculation of force

Substituting the given values into the equation, \(F = 1.79 \times 10^{-3} N \cdot s/m^{2} \times A \times 0.50 m/s / 0.0001 m\). To get \(F = A \times 8.955 N\), the ice block's area \(A\), which would be given in the figure P 9.63, needs to be substituted into this equation to find the force \(F\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Stoke's Law
Stoke's Law is essential for understanding how viscous forces work. It allows us to calculate the force required to move an object through a fluid. The law is given by the formula:
  • \[ F = \eta \frac{Av}{d} \]
In this formula, \(F\) represents the force, \(\eta\) is the viscosity of the fluid, \(A\) stands for the area of the object in contact with the fluid, \(v\) is the velocity, and \(d\) is the distance, such as the thickness of the fluid layer. By understanding and applying Stoke's Law, we can accurately determine how much force is necessary to move an object at a constant speed through a fluid. This is particularly useful in engineering and scientific research applications.
Viscosity of Water
Viscosity is a measure of a fluid's resistance to flow. It describes how "thick" or "sticky" a liquid is. For water at \(0^{\circ}C\), the viscosity value is given as \(\eta = 1.79 \times 10^{-3} \) N·s/m².

Viscosity plays a crucial role when calculating the force needed to move an object through the fluid. The lower the viscosity, the easier it is for an object to move through the fluid, potentially requiring less force. In the context of our ice block and water system, knowing the viscosity of water helps us understand the force interactions arising due to motion.

Understanding viscosity also helps in creating predictions and models for real-world applications such as designing hydraulic machines or studying fluid dynamics in nature.
Unit Conversion
Unit conversion is a critical step in solving physics problems. It ensures that all measurements align with the standard units of the International System of Units (SI).

In this problem, the thickness of the water layer was given in millimeters and needed to be converted to meters. By converting units:
  • 1 mm = 0.001 m, hence 0.10 mm = 0.0001 m.
By doing this, the units in the equation for calculating force remain consistent with the other parameters, which are typically in meters, seconds, and Newtons. Consistent units allow for accurate calculations and meaningful results.
Physics of Motion
The physics of motion involves examining how forces influence the movement of objects. When considering viscous forces and motion through fluids, we look at how these forces oppose the movement.

In this scenario, the ice block moves over a thin layer of water, and the force calculated from Stoke's Law shows how the viscous force acts in the opposite direction of motion. Understanding the balance of forces is crucial to maintaining constant velocity.

This concept also extends beyond simple motion through fluids. It introduces students to broader physics principles, such as Newton's Second Law, which demonstrates the relationship between forces, mass, and acceleration. The knowledge of motion physics is vital for engineering applications, transportation systems, and robotics.

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Most popular questions from this chapter

A certain fluid has a density of \(1080 \mathrm{~kg} / \mathrm{m}^{3}\) and is observed Io rise to a height of \(2.1 \mathrm{~cm}\) in a \(1.0-\mathrm{mm}\) -diameter tube. The contact angle between the wall and the fluid is zcro. Calculate the surface tension of the fluid.

When you suddenly stand up after lying down for a while, your body may not compensate quickly enough for the pressure changes and you might feel dizzy for a moment. If the gauge pressure of the blood at your heart is 13.3 kPa and your body doesn't compensate, (a) what would the pressure be at your head, \(50.0 \mathrm{~cm}\) above your heart? (b) What would it be at your feet, \(1.30 \times 10^{2} \mathrm{~cm}\) below your heart? Hint: The density of blood is \(1060 \mathrm{~kg} / \mathrm{m}^{3}\).

A man of mass \(m=70.0 \mathrm{~kg}\) and having a density of \(\rho=1050 \mathrm{~kg} / \mathrm{m}^{3}\) (while holding his breath) is completely submerged in water. (a) Write Newton's second law for this situation in terms of the man's mass \(m\), the density of water \(\rho_{w}\), his volume \(V\), and \(g\). Neglect any viscous drag of the water. (b) Substitute \(m=\rho V\) into Newtom's second law and solve for the acceleration a, canceling common factors. (c) Calculate the numeric value of the man's acceleration. (d) How long does it take the man to sink \(8.00 \mathrm{~m}\) to the bottom of the lake?

A child slides across a floor in a pair of rubber-soled shoes. The friction force acting on each foot is \(20 \mathrm{~N}\), the footprint area of each foot is \(14 \mathrm{~cm}^{2}\), and the thickness of the soles is \(5.0 \mathrm{~mm}\). Find the horizontal distance traveled by the sheared face of the sole. The shear modulus of the rubber is \(3.0 \times 10^{6} \mathrm{~Pa}\).

On October 21, 2001, Ian Ashpole of the United Kingdom achieved a record altitude of \(3.35 \mathrm{~km}\) (11 000 ft) powered by 600 toy balloons filled with helium. Each filled balloon had a radius of about \(0.50 \mathrm{~m}\) and an estimated mass of \(0.30 \mathrm{~kg}\). (a) Estimate the total buoyant force on the 600 balloons. (b) Estimate the net upward force on all 600 balloons. (c) Ashpole parachuted to Earth after the balloons began to burst at the high altitude and the system lost buoyancy. Why did the balloons burst?

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