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A certain fluid has a density of \(1080 \mathrm{~kg} / \mathrm{m}^{3}\) and is observed Io rise to a height of \(2.1 \mathrm{~cm}\) in a \(1.0-\mathrm{mm}\) -diameter tube. The contact angle between the wall and the fluid is zcro. Calculate the surface tension of the fluid.

Short Answer

Expert verified
The calculated surface tension \(T\) will be the solution once you make the necessary computations using the given values and formula.

Step by step solution

01

Identify the given information

Density of fluid \(蟻 = 1080 \mathrm{~kg} / \mathrm{m}^{3}\), height of the fluid rise \(h = 2.1 \mathrm{~cm}\) = 0.021 \mathrm{~m}\), contact angle \(胃 = 0\) degrees, diameter of the tube is 1.0 mm which gives a radius \(r\) of 0.5 mm = \(0.0005 \mathrm{~m}\). You also know that gravitational acceleration \(g = 9.81 \mathrm{~m/s}^{2}\).
02

Substitute the given values into the formula

Plug the given values into the formula \(T = \frac{蟻grh}{2}\) to solve for \(T\).
03

Compute

Calculate the value of \(T\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Surface Tension
Surface tension is a fascinating property of fluids that makes it seem as though the surface of a liquid is covered with a thin elastic sheet. This phenomenon occurs due to the cohesive forces between the molecules at the surface of the liquid, which are greater than those between the liquid and the air above it.
These forces cause the liquid to minimize its surface area, leading to effects like water droplets forming beads on a surface.

In the context of the exercise, surface tension (\( T \)) is crucial for determining how high a fluid will rise in a capillary tube, known as capillary action. To calculate the surface tension when dealing with capillary action, we use the formula:
  • \( T = \frac{蟻grh}{2} \)
Here, \( 蟻 \) is the density of the fluid, \( g \) is the acceleration due to gravity, \( r \) is the radius of the tube, and \( h \) is the height the fluid rises. This relationship stems from the balance of forces between gravity pulling the fluid down and surface tension lifting it up.
Capillary Action
Capillary action is the ability of a liquid to flow in narrow spaces without the assistance of external forces, or even in opposition to them. It's what you see when water climbs up a thin tube, or when you dip the tip of a paper towel in water and watch it climb.
This action occurs because of the adhesive forces between the liquid and the walls of the container or tube, combined with the cohesive forces within the liquid itself.

In the exercise, the fluid rises due to capillary action, which is prevalent in tubes or porous materials. When the contact angle is zero, the adhesion between the fluid and the tube walls is maximized, resulting in the maximum rise of the liquid. The fluid continues to move against gravity because the surface tension creates a force that pulls the fluid up, counteracting the downward pull of gravity.
Density
Density is a measure of how much mass a substance contains in a given volume. It is expressed in units like kg/m鲁 and is a fundamental concept in fluid mechanics, as it influences a liquid's behavior considerably.
The fluid in the exercise has a density of \( 1080 \text{ kg/m}^3 \), which affects how it interacts with its environment and how high it can rise in the tube under the force of gravity.

The density of the fluid influences the capillary rise, as it is part of the formula \( T = \frac{蟻grh}{2} \), where it is directly proportional to both the gravitational force pulling down on the fluid and the surface tension force pulling it up. Thus, a higher density fluid will, under the same conditions, rise to a lesser height compared to a lower density fluid.
Contact Angle
The contact angle is the angle at which a liquid interface meets a solid surface. It is a measure of the wettability of a solid by a liquid. When the contact angle is low, it implies good wetting of the surface by the liquid; when it is high, it implies poor wetting.
A zero contact angle, as in the exercise, indicates perfect wetting, which means the liquid completely spreads across the surface without forming a bulge.

The contact angle affects capillary action significantly. With a contact angle of zero, the liquid's adhesive forces with the wall are maximized, aiding the liquid to rise higher in the capillary tube. When calculating the rise in such a situation, the formula simplifies as the zero contact angle means only considering surface tension and gravity.

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A \(62.0-\mathrm{kg}\) survivor of a cruise line disaster rests atop a block of Styrofoam insulation, using it as a raft. The Styrofoam has dimensions \(2.00 \mathrm{~m} \times 2.00 \mathrm{~m} \times 0.0900 \mathrm{~m}\). The bottom \(0.024 \mathrm{~m}\) of the raft is submerged. (a) Draw a free-body diagram of the system consisting of the survivor and raft. (b) Write Newton's second law for the system in one dimension, using \(B\) for buoyancy, \(w\) for the weight of the survivor, and \(w_{r}\) for the weight of the raft. (Set \(a=0 .\) ) (c) Calculate the numeric value for the buoyancy, \(B\). (Seawater has density \(1025 \mathrm{~kg} / \mathrm{m}^{3}\).) (d) Using the value of \(B\) and the weight w of the survivor, calculate the weight \(w_{r}\) of the Styrofoam. (c) What is the density of the Styrofoam? (f) What is the maximum buoyant force, corresponding to the raft being submerged up to its top surface? (g) What total mass of survivors can the raft support?

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