/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 60 Be To lift a wire ring of radius... [FREE SOLUTION] | 91Ó°ÊÓ

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Be To lift a wire ring of radius \(1.75 \mathrm{~cm}\) from the surface of a container of blood plasma, a vertical force of \(1.61 \times\) \(10^{-2} \mathrm{~N}\) greater than the weight of the ring is required. Calculate the surface tension of blood plasma from this information.

Short Answer

Expert verified
The surface tension of the blood plasma is \(0.146\) N/m.

Step by step solution

01

Convert radius to meters

The radius is given in centimeters. However, in physics problems, it is standard to use SI units. So, convert the radius from cm to m by multiplying with 0.01. \(r = 1.75 \times 0.01 = 0.0175\) m.
02

Calculate the circumference of the ring

The length of the contact line between the ring and the liquid is the circumference of the ring, which can be calculated using the formula \(2Ï€r\). So, the circumference of the ring is \(2Ï€ \times 0.0175 = 0.11\) m.
03

Calculate the surface tension

Now, you can calculate the surface tension of the blood plasma using the formula \(T = F / 2Ï€r\). The force (F) is given to be \(1.61 \times 10^{-2}\) N. Substituting the values of F and r in the formula, we get \(T = (1.61 \times 10^{-2}) / 0.11 = 0.146\) N/m.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Force Calculation
The concept of force calculation is fundamental in physics, particularly when exploring interactions like surface tension. Surface tension is a force that acts along the surface of a liquid, and it can be measured by the amount of force required to lift an object off that surface. In the problem at hand, we calculate the force needed to lift a wire ring. This force is slightly more than the weight of the ring itself, as given by the exercise: a total vertical force of \(1.61 \times 10^{-2}\ \text{N}\) is needed.
  • Surface tension acts around the circumference of the ring, causing a uniform pulling force in the upward direction.
  • To find this, we needed to understand how the force relates to the contact line of the ring, which is essential in solving for surface tension.
By grasping these ideas, you'll find force calculation becomes clearer, especially as it pertains to the "pull" at a liquid's surface, which is quantified as surface tension.
SI Units Conversion
SI units form the basis for calculations in physics, offering a universal standard. It's crucial to understand how to convert measurements to these units, as it simplifies calculations and ensures consistency across scientific inquiries. In the original exercise, the radius was provided in centimeters (\(\text{cm}\)).
  • Converting centimeters to meters, the standard SI unit for length, involves multiplying by 0.01.
  • This conversion is essential since the calculation for circumference, and subsequently surface tension, must be done in meters.
Thus, we convert \(1.75\ \text{cm}\) to \(0.0175\ \text{m}\) to align with SI units, allowing precise calculations. Mastering SI conversions is a vital skill for success in physics, providing the foundation for accurate measurement and computational consistency.
Contact Line
When calculating surface tension, recognizing the concept of the contact line is key. The contact line is essentially the boundary where the liquid meets the solid object—in this case, the wire ring. Understanding the length of this line is crucial because it determines how the liquid exerts its force.
  • For a circular wire ring, the contact line corresponds to the circumference of the circle.
  • This is calculated with the formula \(2\pi r\), which gives you the complete perimeter around the wire that the liquid adheres to.
Here, the circumference calculation produces \(0.11\ \text{m}\), establishing the total length of the contact line. Recognizing how to calculate and apply the contact line in problems allows you to better understand the distribution of forces acting through surface tension, showcasing a seamless synergy between geometry and physics.

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Most popular questions from this chapter

The average human has a density of \(945 \mathrm{~kg} / \mathrm{m}^{3}\) after inhaling and \(1020 \mathrm{~kg} / \mathrm{m}^{3}\) after exhaling. (a) Without making any swimming movements, what percentage of the human body would be above the surface in the Dead Sea (a lake with a water density of about \(1230 \mathrm{~kg} / \mathrm{m}^{3}\) ) in each of these cases? (b) Given that bone and muscle are denser than fat, what physical characteristics differentiate "sinkers" (those who tend to sink in water) from "floaters" (those who readily float)?

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Suppose two worlds, each having mass \(M\) and radius \(R\), coalesce into a single world. Due to gravitational contraction, the combined world has a radius of only \({ }_{4}^{3} R\). What is the average density of the combined world as a multiple of \(\rho_{0}\), the average density of the original two worlds?

The nucleus of an atom can be modeled as several protons and neutrons closely packed together. Each particle has a mass of \(1.67 \times 10^{-27} \mathrm{~kg}\) and radius on the order of \(10^{-15} \mathrm{~m}\). (a) Use this model and information to estimate the density of the nucleus of an atom. (b) Compare your result with the density of a material such as iron. What do your result and comparison suggest about the structure of matter?

A spherical weather balloon is filled with hydrogen until its radius is \(3.00 \mathrm{~m}\). Its total mass including the instruments it carries is \(15,0 \mathrm{~kg}\). (a) Find the buoyant force acting on the balloon, assuming the density of air is \(1.29 \mathrm{~kg} / \mathrm{m}^{3}\). (b) What is the net force acting on the balloon and its instruments after the balloon is released from the ground? (c) Why does the radius of the balloon tend to increase as it rises to higher altitude?

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