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When you suddenly stand up after lying down for a while, your body may not compensate quickly enough for the pressure changes and you might feel dizzy for a moment. If the gauge pressure of the blood at your heart is 13.3 kPa and your body doesn't compensate, (a) what would the pressure be at your head, \(50.0 \mathrm{~cm}\) above your heart? (b) What would it be at your feet, \(1.30 \times 10^{2} \mathrm{~cm}\) below your heart? Hint: The density of blood is \(1060 \mathrm{~kg} / \mathrm{m}^{3}\).

Short Answer

Expert verified
The pressure at the head would be less than the starting pressure of 13.3 kPa due to it being above the heart, while the pressure at the feet would be more than 13.3 kPa due to it being below the heart. The exact values are found by calculating the expressions derived in steps 1 and 3.

Step by step solution

01

Find the pressure at the head

To find the pressure at the head, which is above the heart, we use the formula \(P_2 = P_1 - \rho g h\) as the pressure decreases with height in the fluid. Inputting given values, we get \(P_{2(head)} = 13.3 kPa - (1060 kg/m³)(9.8 m/s²)(50.0 cm = 0.5 m)\)
02

Calculate the pressure at the head

Calculate the expression obtained in step 1 to find the value of \(P_{2(head)}\). This will be the pressure at the head while standing up.
03

Find the pressure at the feet

To find the pressure at the feet, which is below the heart, we use the formula \(P_2 = P_1 + \rho g h\) as the pressure increases with depth in the fluid. Inputting given values, we get \(P_{2(feet)} = 13.3 kPa + (1060 kg/m³)(9.8 m/s²)(1.30 × 10² cm = 1.3 m)\)
04

Calculate the pressure at the feet

Calculate the expression obtained in step 3 to find the value of \(P_{2(feet)}\). This will be the pressure at the feet while standing up.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gauge Pressure
In fluid mechanics, gauge pressure is a term that refers to the pressure measurement relative to the ambient atmospheric pressure. Gauge pressure is often used because it represents the actual pressure measurement minus the atmospheric pressure, which could make physical analysis and geometrical reasoning straightforward. For example, when blood pressure is measured in your body, the gauge pressure is noted to exclude atmospheric influence. This is particularly relevant when considering internal biological pressures, ensuring that the values only reflect the blood’s influence. However, it’s important to remember that gauge pressure doesn’t indicate total pressure, as it doesn’t account for atmospheric pressure outside the system.
Density of Blood
Density, especially the density of blood in this scenario, plays a crucial role when calculating pressure differences throughout the body. The density of blood is approximately 1060 kilograms per cubic meter \( \text{kg/m}^3 \). This density slightly varies for individuals based on several health and biological factors, but standard values allow for typical calculations. When blood density comes into play in fluid mechanics, it assists in determining how pressure varies between different points in the body. Having a high density means that under gravitational effect, blood can exert significant pressure differences, depending on whether you're lying down or standing up.
Pressure Calculation
Pressure in a fluid can vary based on depth and height, making calculations essential to understand physical behaviors under different conditions. To calculate pressure at a certain point, you can make use of the formula:\[P = P_1 \pm \rho g h\]where:
  • \(P\) is the pressure at the point of interest,
  • \(P_1\) is the reference pressure,
  • \(\rho\) is the fluid's density,
  • \(g\) is the acceleration due to gravity, and
  • \(h\) is the height difference.
The sign in the equation depends on whether you’re working with depths below a reference point (additive) or heights above (subtractive). For instance, calculating pressure at the head above the heart involves subtracting because you’re moving against gravity, resulting in reduced pressure. This concept allows us to visualize how different parts of the body experience varying pressures.
Gravitational Force
Gravitational force is central to understanding how fluid pressures change as you move within a gravitational field. On Earth, the force due to gravity is approximately \(9.8 \, \mathrm{m/s^2}\), and it acts on all objects with mass including fluids. This force not only keeps us grounded but is essential in pressure calculations within fluids such as blood.

Gravity acts on each element of a fluid, giving it weight, which in turn contributes to the fluid pressure. When moving upwards against gravity, as in the calculations for pressure at the head, you experience a decrease in pressure because gravity is acting opposite to the motion. Conversely, moving deeper within a fluid, as when calculating pressure at the feet, results in increased pressure due to the additional weight of the fluid column above.

Understanding gravitational force not only aids in pressure calculations but also illustrates why pressure differences are significant when changing position from lying to standing.

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Most popular questions from this chapter

A sample of an unknown material appears to weigh \(300 \mathrm{~N}\) in air and \(200 \mathrm{~N}\) when immersed in alcohol of specific gravicy \(0.700 .\) What are (a) the volume and (b) the density of the material?

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Whole blood has a surface tension of \(0.0 .58 \mathrm{~N} / \mathrm{m}\) and a density of \(1050 \mathrm{~kg} / \mathrm{m}^{3}\). To what height can whole blood rise in a capillary blood vessel that has a radius of \(2.0 \times 10^{-6} \mathrm{~m}\) if the contact angle is zero?

The nucleus of an atom can be modeled as several protons and neutrons closely packed together. Each particle has a mass of \(1.67 \times 10^{-27} \mathrm{~kg}\) and radius on the order of \(10^{-15} \mathrm{~m}\). (a) Use this model and information to estimate the density of the nucleus of an atom. (b) Compare your result with the density of a material such as iron. What do your result and comparison suggest about the structure of matter?

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