/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 36 A man of mass \(m=70.0 \mathrm{~... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A man of mass \(m=70.0 \mathrm{~kg}\) and having a density of \(\rho=1050 \mathrm{~kg} / \mathrm{m}^{3}\) (while holding his breath) is completely submerged in water. (a) Write Newton's second law for this situation in terms of the man's mass \(m\), the density of water \(\rho_{w}\), his volume \(V\), and \(g\). Neglect any viscous drag of the water. (b) Substitute \(m=\rho V\) into Newtom's second law and solve for the acceleration a, canceling common factors. (c) Calculate the numeric value of the man's acceleration. (d) How long does it take the man to sink \(8.00 \mathrm{~m}\) to the bottom of the lake?

Short Answer

Expert verified
Firstly, the forces acting on the man were identified and Newton's Second Law of Motion was applied. This led to an equation was derived for the acceleration of the man. Substituting known quantities, the acceleration was calculated. Finally, using the equations of motion, the time taken for the man to sink to the bottom of the lake was determined.

Step by step solution

01

Identify the forces acting on the man

When the man is submerged in water, two forces will primarily act on him. The first is his weight acting downwards, given by \(mg\) where \(m\) is his mass and \(g\) is the acceleration due to gravity. The second is the buoyant force acting upwards, given by the volume of the displaced water multiplied by its density and the acceleration due to gravity, i.e., \( \rho_{w} g V\), where \( \rho_{w}\) is the density of water and \(V\) is his volume.
02

Use Newton's Second Law of Motion

According to Newton's Second Law of Motion, the net force acting on a body is equal to the product of its mass and acceleration. For the man, this is expressed as \( m a = m g - \rho_{w} g V \).
03

Substitute \( m = \rho V \)

By substituting the value of \( m \) into Newton's second law equation, we get \( \rho V a = \rho g V - \rho_{w} g V \). Cancelling common terms gives \( a = g - \rho_{w} g \).
04

Calculate the acceleration

To compute the acceleration, substitute the values of g and \( \rho_{w}\) into the equation from step 3. The acceleration due to gravity \(g\) is approximately \(9.8 \, \mathrm{m/s^{2}}\) and the density of water \( \rho_{w}\) is approximately \(1000 \, \mathrm{kg/ m^{3}}\). This will give you \( a = g (1 - \rho_{w} / \rho) \).
05

Calculate the time to sink 8.00 m

From kinematics, the equation relating distance, initial velocity, acceleration and time is \( d = v_{i} t + 0.5 a t^{2} \). Here, \( v_{i} = 0 \), since the man starts from rest, and \( d = 8.00 \, m \), which is the depth of the lake. Solving this equation for time \( t \) will give the time it takes the man to sink to the bottom of the lake.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Buoyant Force
The buoyant force is a key concept in fluid dynamics and plays a vital role in understanding how objects behave when submerged in a fluid. Imagine placing an object in water; it will experience an upward force because the fluid below it is pushing harder than the fluid above, due to fluid pressure increasing with depth. This force is what we call the buoyant force.

The magnitude of the buoyant force is equal to the weight of the fluid displaced by the object, which can be calculated using the formula \( F_b = \rho_w g V \), where \( F_b \) is the buoyant force, \( \rho_w \) represents the density of the fluid (water, in this case), \( g \) is the acceleration due to gravity, and \( V \) is the volume of the object submerged. This principle is known as Archimedes' Principle, and it explains why objects that are less dense than the fluid they are submerged in will float, while denser objects will sink.

Additionally, understanding buoyant force is crucial when calculating the net force acting on submerged objects, like in our exercise.
Density and Buoyancy
Density and buoyancy are inseparable when discussing the buoyant force and the behavior of objects in fluids. Density is defined as the mass per unit volume of a substance and is expressed as \( \rho = \frac{m}{V} \) with \( m \) being the mass and \( V \) the volume. The comparison between the density of an object and the density of the fluid in which it is submerged dictates its buoyancy.

An object will float if its density is less than that of the fluid, meaning it is buoyant, and it will sink if its density is greater. In the given exercise, the man's body density while holding his breath is greater than the density of the water, hence the reason he sinks.

When calculating the acceleration of the submerged man, understanding that his mass \( m \) can be expressed in terms of his density and volume \( m = \rho V \) simplifies the application of Newton's second law. This allows us to see how the man's buoyancy, due to his own density in relation to the water's density, affects his acceleration under gravity.
Kinematic Equations
The kinematic equations allow us to describe the motion of objects using parameters such as displacement, velocity, acceleration, and time. These equations derive from calculus and tell the story of how an object moves. One of these equations, which involves constant acceleration, is \( d = v_i t + \frac{1}{2} a t^2 \).

Applying this equation in our scenario helps us to find out how long it takes for the man to reach the bottom of the lake. In the exercise, we consider the initial velocity (\(v_i\)) to be zero since the man is starting from rest and the total distance (\(d\)) is the depth of the lake he sinks through.

With the previously calculated acceleration (\(a\)), the time (\(t\)) can be computed by rearranging the kinematic equation to solve for \(t\). This process exemplifies the use of kinematics in real-world applications, making it an essential part of physics and engineering problems involving motion.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Water is pumped through a pipe of diameter \(15.0 \mathrm{~cm}\) from the Colorado River up to Grand Canyon Village, on the rim of the canyon. The river is at \(564 \mathrm{~m}\) elevation and the village is at \(2096 \mathrm{~m}\). (a) At what minimum pressure must the water be pumped to arrive at the village? (b) If \(4500 \mathrm{~m}^{3}\) are pumped per day, what is the speed of the water in the pipe? (c) What additional pressure is necessary to deliver this flow? Note: You may assume the free-fall acceleration and the density of air are constant over the given range of elevations.

A hypodermic syringe contains a medicine with the density of water (Fig, \(\mathrm{P} 9.47)\). The barrel of the syringe has a cross-sectional area of \(2.50 \times 10^{-5} \mathrm{~m}^{2}\). In the absence of a force on the plunger, the pressure everywhere is \(1.00 \mathrm{~atm} . \mathrm{A}\) force \(\mathbf{F}\) of magnitude \(2.00 \mathrm{~N}\) is exerted on the plunger, making medicine squirt from the needle. Determine the medicine's flow speed through the necdle. Assume the pressure in the needle remains equal to \(1.00\) atm and that the syringe is horizontal.

Bone has a Young's modulus of about \(18 \times 10^{9} \mathrm{~Pa}\). Under compression, it can withstand a stress of about 160 \(\times 10^{6} \mathrm{~Pa}\) before breaking. Assume that a femur (thigh- bone) is \(0.50 \mathrm{~m}\) long, and calculate the amount of compression this bone can withstand before breaking.

The approximate inside diameter of the aorta is \(0.50 \mathrm{~cm} ;\) that of a capillary is \(10 \mu \mathrm{m}\). The approximate average blood flow speed is \(1.0 \mathrm{~m} / \mathrm{s}\) in the aorta and \(1.0 \mathrm{~cm} / \mathrm{s}\) in the capillaries. If all the blood in the aorta eventually flows through the capillaries, estimate the number of capillaries in the circulatory system.

The block of ice (temperature \(0^{\circ} \mathrm{C}\) ) shown in Figure \(\mathrm{P} 9.63\) is drawn over a level surface lubricated by a layer of water \(0.10 \mathrm{~mm}\) thick. Determine the magnitude of the force \(\vec{F}\) needed to pull the block with a constant speed of \(0.50 \mathrm{~m} / \mathrm{s}\). At \(0^{\circ} \mathrm{C}\), the viscosity of water has the value \(\eta=1.79 \times 10^{-3} \mathrm{~N} \cdot \mathrm{s} / \mathrm{m}^{2}\)

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.