/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 29 The volume of a gas is halved du... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The volume of a gas is halved during an adiabatic compression that increases the pressure by a factor of 2.5.

a. What is the specific heat ratio g?

b. By what factor does the temperature increase?

Short Answer

Expert verified

The answer for (a) is1.90Land (b) is74°C.

Step by step solution

01

Description 

As per provided information, the volume of a gas is halved during an adiabatic compression that increases the pressure by a factor of 2.5.

On the basis of adiabatic process, it can be written as:

p1V2γ=p2V2γ

02

Result on finding the heat ratio g and temperature 

On the basis of adiabatic process, it can be written as:

p1V2γ=p2V2γ

On the basis of second volume:

(V2V1)γ=p1p2⇒V1V2=p1p2γ

Therefore,

V2=V1p1p2γ

On the basis of ideal gas law and numerically

V2=0.1·8.314·4233.10130021.40=1.90L

Thus, as per the ideal gas law when mole number is constant:

p1V1T1=p2V2T2

Therefore, the temperature is on the basis of numerics:

T2=1221.4·423=347K

On the basis of Celcius:

347K=347-273=74°C

Therefore, the answer for (a) is 1.90Land (b) is 74°C.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

10 g of aluminum at 200°C and 20 g of copper are dropped into 50 cm3 of ethyl alcohol at 15°C. The temperature quickly comes to 25°C. What was the initial temperature of the copper?

A cube 20cm on each side contains 3.0g of helium at 20°C. 1000J of heat energy are transferred to this gas. What are (a) the final pressure if the process is at constant volume and (b) the final volume if the process is at constant pressure? (c) Show and label both processes on a single pV diagram.

A 6.0cmdiameter cylinder of nitrogen gas has a 4.0cm-thick movable copper piston. The cylinder is oriented vertically, as shown in FIGURE P19.50, and the air above the piston is evacuated. When the gas temperature is20∘C,the piston floats 20cmabove the bottom of the cylinder.

a. What is the gas pressure?

b. How many gas molecules are in the cylinder? Then 20∘Cof heat energy are transferred to the gas.

c. What is the new equilibrium temperature of the gas?

d. What is the final height of the piston?

e. How much work is done on the gas as the piston rises?

500 J of work must be done to compress a gas to half its initial volume at constant temperature. How much work must be done to compress the gas by a factor of 10, starting from its initial volume?

Shows two different processes taking an ideal gas from state i to state f.

a. Is the temperature change ∆T during process A larger than, smaller than, or equal to the change during process B? Explain.

b. Is the heat energy added during process A greater than, less than, or equal to the heat added during process B? Explain.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.