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What is the maximum mass of ethyl alcohol you could boil with 1000 J of heat, starting from 20C?

Short Answer

Expert verified

The answer ism=1.01[g]

Step by step solution

01

Given information

The total heat of ethynyl alcohol is

Q=Q1+Q2 (1)

The change in temperature as per the equation (19.16) is:

Q1=Mc∆T (2)

02

Calculation

M is the mass of ethynyl alcohol

plug the values of ∆TandCinto equation (3) in order to get Q1

Q1=Mc(T2-T1)=M(2400J/kg.C°)(78°C-20°C)=(1.39×105J)M

The heatQ2 as a result of phase changes provided in the equation (19.21) is:
Q2=MLv

Thus, plug the value of Lvinto equation (3) in order to get Q2

Q2=MLv=(8.79×105J/kg)m

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