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Chapter 19: Q. 13 (page 543)

A rapidly spinning paddle wheel raises the temperature of 200 mL of water from 21掳C to 25掳C. How much

(a) heat is transferred and

(b) work is done in this process?

Short Answer

Expert verified

a. The value of heat is zero

b. The work done energy is 3.4kJ bfvbyfv

Step by step solution

01

Definition of adiabatic process 

This process has ben seen when heat or energy doe not transfer from one system to other. So the amount of heat is zero.

02

Finding the value of work done energy 

a. Thermal energy for the charges of temperature is Ethi=Mc鈭�T

As Q=0J , so W=Ethi=Mc鈭�T

b. Now M is material and its equation is M=蚁V=1g/ml200ml=0.2kg

Applying all values of M, c, T1,T2

The work done is

=Mc(T2-T1)=0.2kg4190J/K.Co25-21oC=3.4kJ

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