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A 70kg human sprinter can accelerate from rest to 10m/s in 3.0s. During the same time interval, a30 kg greyhound can go from rest to 20 m/s. What is the average power output of each? Average power over a time interval t is Et

Short Answer

Expert verified

Average power output of sprinter is1166.67Wand of greyhound is2000W.

Step by step solution

01

Concept

Concept:
The K.E. of an object moving with velocity is v
K=12mv2
Here m is that the mass ofthe thing.
The average output is calculated by dividing the ultimate mechanical energy by the quantity of your time it tookto induce that energy:
P=K
Here t is that the time.
Substitute the expression for K.E. within the above equation.

P=12mv2t

02

Typical Power

In the case of the sprinter,the typical power output is:
P=12mv2t
Substitute 70kgfor mass,20m/sfor speed and 3sfor time.

P=12(70kg)(10m/s)23s

=1166.67W

03

Step 3. Average power output 

The greyhound's average power output is:
P=12mv2t

Substitute 30kgfor mass, 10m/sfor speed, and3sfor time.

P=12(30kg)(20m/s)23s

=2000W


So, the greyhound is truly outputting more average power than the sprinter in this period of timel

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