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A 60kg student is standing atop a spring in an elevator as it accelerates upward at 3.0m/s2. The spring constant is2500 N/m. By how much is the spring compressed?

Short Answer

Expert verified

The spring compresseds=31cm

Step by step solution

01

Step 1. Given Information

The mass m=60kg

Acceleration a=3.0m/s

The spring constantk=2500N/m

02

Step 2. Hooke's law

When a spring is compressed, a force is exerted by its material to restore it to its equilibrium position and its force is called restoring force Fsp. Hooke's law states the relationship between the restoring force and the displacement s

Fsp=ks

03

Step 3. How much is spring compressed

The spring force is exerted in an opposite direction to the weight of the student, so the net force that is exerted on the student is

Fnet=Fsp-mgma=ks-mgs=m(a+g)k

Now, put the values

s=m(a+g)k=(60kg)(3m/s2+9.8m/s2)2500N/m=0.31m=31cm

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