/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 28 A 60聽kg student is standing ato... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 9: Q. 28 (page 228)

A 60kg student is standing atop a spring in an elevator as it accelerates upward at 3.0m/s2. The spring constant is2500 N/m. By how much is the spring compressed?

Short Answer

Expert verified

The spring compressed鈭�s=31cm

Step by step solution

01

Step 1. Given Information

The mass m=60kg

Acceleration a=3.0m/s

The spring constantk=2500N/m

02

Step 2. Hooke's law

When a spring is compressed, a force is exerted by its material to restore it to its equilibrium position and its force is called restoring force Fsp. Hooke's law states the relationship between the restoring force and the displacement 鈭�s

Fsp=k鈭�s

03

Step 3. How much is spring compressed

The spring force is exerted in an opposite direction to the weight of the student, so the net force that is exerted on the student is

Fnet=Fsp-mgma=k鈭�s-mg鈭�s=m(a+g)k

Now, put the values

鈭�s=m(a+g)k=(60kg)(3m/s2+9.8m/s2)2500N/m=0.31m=31cm

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Two identical horizontal springs are attached to opposite sides of a box that sits on a frictionless table. The outer ends of the springs are clamped while the springs are at their equilibrium lengths. Then a 2.0N force applied to the box, parallel to the springs, compresses one spring by 3.0cm while stretching the other by the same amount. What is the spring constant of the springs?

In Problems 67 through 69 you are given the equation(s) used to solve a problem. For each of these, you are to

a. Write a realistic problem for which this is the correct equation(s).

b. Draw a pictorial representation.

c. Finish the solution of the problem

Fpush-(0.20)(30kg)(9.8m/s2)=075W=Fpushv

In Problems 67 through 69you are given the equation(s) used to solve a problem. For each of these, you are to

a. Write a realistic problem for which this is the correct equation(s).

b. Draw a pictorial representation.

c. Finish the solution of the problem

12(2.0kg)(4.0m/s2)+0+(0.15)(2.0)(9.8m/s2)(2.0)=0+0+T(2.0m)

A 50kgice skater is gliding along the ice, heading due north at 4.0m/s. The ice has a small coefficient of static friction, to prevent the skater from slipping sideways, but 渭k=0. Suddenly, a wind from the northeast exerts a force of 4.0N on the skater.

a. Use work and energy to find the skater鈥檚 speed after gliding 100m in this wind.

b. What is the minimum value of 渭s that allows her to continue moving straight north?

Particle A has half the mass and eight times the kinetic energy of particle B. What is the speed ratio vA/vB?
See all solutions

Recommended explanations on Physics Textbooks

Electric Charge Field and Potential

Read Explanation

Modern Physics

Read Explanation

Magnetism

Read Explanation

Astrophysics

Read Explanation

Oscillations

Read Explanation

Measurements

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.