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A particle moving on the x-axis experiences a force given by Fx=qx2 , where q is a constant. How much work is done on the particle as it moves from x=0 to x=d?

Short Answer

Expert verified

Work done by particleW0→d=qd33

Step by step solution

01

Step 1. Given information

We have,

ForceFx=qx3

qis constant

02

Step 2. Find the expression for the work done in the interval

A force F that acted on an object with mass m is parallel to the direction of motion and causes displacement delta rightarrowx for that object

W=∫Fxdx

We are given the force as a function of x by Fx=qx2

W=∫Fxdx=∫0dqx2dx=q∫0dx2dx=q13x3

Now,

W0→d=q13d3-13(0)3=qd33

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