/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 7 On a screen behind such a diffra... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

On a screen behind such a diffracting grating, narrow, bright fringes can be seen. After that, the entire research is submerged in water. Do the screen's fringes get closer together, farther apart, stay the same, or simply disappear? Explain

Short Answer

Expert verified

n(asinθ)=mλ₶Ä

The fringes move away from each other.

Step by step solution

01

Explanation of the Diffraction Experiment

The diffraction experiment having interference pattern fringes is described by

asinθ=mλ₶Ä

The experiment is assumed to mean having emptied the air in this equation.n=1

02

The Wavelength Changed

When the identical comparison is made in water, the wavelength changes.

λₙ=λ₶Ä/n

execution for constructive interference.

asinθ=mλₙ

03

Step 3:  Substitution

We substitute

asinθ=mλ/n

n(asinθ)=mλ₶Ä

The spectral separation is amplified by the same wavelength because water has an index of refraction of n=1.33, so the fringe moves away from one another.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

It shows the light intensity on a viewing screen behind a circular aperture. What happens to the width of the central maximum if the

a. The wavelength of the light is increased.

b. The diameter of the aperture is increased.

c. How will the screen appear if the aperture diameter is less than the light wavelength?

FIGUREP33.36shows the light intensity on a screen behind a double slit. The slit spacing is 0.20mmand the wavelength of the light is 620nm. What is the distance from the slits to the screen?

Scientists shine a laser beam on a 35-μm-wide slit and produce a diffraction pattern on a screen 70cmbehind the slit. Careful measurements show that the intensity first falls to 25%of maximum at a distance of7.2mmfrom the center of the diffraction pattern. What is the wavelength of the laser light?

Hint: Use the trial-and-error technique demonstrated in Example 33.5to solve the transcendental equation.

A Michelson interferometer operating at a 600nmwavelength has a 2.00-cm-long glass cell in one arm. To begin, the air is pumped out of the cell and mirror M2is adjusted to produce a bright spot at the center of the interference pattern. Then a valve is opened and air is slowly admitted into the cell. The index of refraction of air at 1.00atmpressure is 1.00028. How many brightdark-bright fringe shifts are observed as the cell fills with air?

Light of630nmwavelength illuminates a single slit of width 0.15mm. FIGURE EX33.17shows the intensity pattern seen on a screen behind the slit. What is the distance to the screen?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.