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FIGURE shows the light intensity on a viewing screen behind a single slit of width a. The light鈥檚 wavelength is . Is <a,=a, >a, oris it not possible to tell? Explain.

Short Answer

Expert verified

Behind a single slit, the light intensity on a viewing screen is<a

Step by step solution

01

Introduction

When it comes to waves like acoustic waves (sound) or electromagnetic waves like light or radio waves, intensity refers to the average power transfer across one period of the wave. Intensity can be used in a variety of situations where energy is delivered. For example, the intensity of the kinetic energy carried by drops of water from a garden sprinkler may be calculated.

02

Step 2:  Explanation

As sin1, the first minima from the central maximum need asin()1=, which must be smaller than1.

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Most popular questions from this chapter

Light from a helium-neon laser (=633nm) is incident on a single slit. What is the largest slit width for which there are no minima in the diffraction pattern?

Light of wavelength550nm illuminates a double slit, and the interference pattern is observed on a screen. At the position of the m=2 bright fringe, how much farther is it to the more distant slit than to the nearer slit?

FIGURE shows two nearly overlapped intensity peaks of the sort you might produce with a diffraction grating . As a practical matter, two peaks can just barely be resolved if their spacing yequals the width w of each peak, where wis measured at half of the peak鈥檚 height. Two peaks closer together than wwill merge into a single peak. We can use this idea to understand the resolution of a diffraction grating.

a. In the small-angle approximation, the position of the m=1peak of a diffraction grating falls at the same location as the m=1fringe of a double slit: y1=L/d. Suppose two wavelengths differing by lpass through a grating at the same time. Find an expression for localid="1649086237242" y, the separation of their first-order peaks.

b. We noted that the widths of the bright fringes are proportional to localid="1649086301255" 1/N, where localid="1649086311478" Nis the number of slits in the grating. Let鈥檚 hypothesize that the fringe width is localid="1649086321711" w=y1/NShow that this is true for the double-slit pattern. We鈥檒l then assume it to be true as localid="1649086339026" Nincreases.

c. Use your results from parts a and b together with the idea that localid="1649086329574" ymin=wto find an expression for localid="1649086347645" min, the minimum wavelength separation (in first order) for which the diffraction fringes can barely be resolved.

d. Ordinary hydrogen atoms emit red light with a wavelength of localid="1649086355936" 656.45nm.In deuterium, which is a 鈥渉eavy鈥 isotope of hydrogen, the wavelength is localid="1649086363764" 656.27nm.What is the minimum number of slits in a diffraction grating that can barely resolve these two wavelengths in the first-order diffraction pattern?

FIGUREP33.49shows the interference pattern on a screen 1.0mbehind an 800line/mmdiffraction grating. What is the wavelength (in mm) of the light?

Two narrow slits 80渭尘apart are illuminated with light of wavelength localid="1649170764860" 620nm. What is the angle of thelocalid="1649170756737" m=3bright fringe in radianslocalid="1649170769758" ?In degreeslocalid="1649170772775" ?

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