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Let, A→=2i^+3j^,B→=2i^-4j^andC→=A→+B→.

a. Write vector C→in component form.

b. Draw a coordinate system and on it show vectors A→,B→andC→.

c. What are the magnitude and direction of vectorC→?

Short Answer

Expert verified

(a) C→=4i^-j^.

(b) The graph is,

(c) The magnitude of C→is17and the direction is-14∘.

Step by step solution

01

Part (a) Step 1. Given information

It is given that A→=2i^+3j^,B→=2i^-4j^andC→=A→+B→.We need to determine the vector C→in component form.

02

Step 2. Solution

A→=2i^+3j^,B→=2i^-4j^.

role="math" C→=A→+B→.

role="math" localid="1649230879168" =2i^+3j^+2i^-4j^.

=2+2i^+3-4j^.

=4i^-j^.

03

Part (b) Step 1. Given information

It is given that,A→=2i^+3j^,B→=2i^-4j^andC→=A→+B→.We need to draw the coordinate system.

04

Step 2. Graph of the A→,B→ and C→

The graph ofA→,B→andC→is,

05

Part (c) Step 1. Given information

It is given that, A→=2i^+3j^,B→=2i^-4j^andC→=A→+B→.We need to determine the magnitude and the direction of the vectorC→.

06

Step 2. Calculation

From part (a) C→=4i^-j^.

Thus, Cx=4,Cy=-1.

C=Cx2+Cy2.

=42+-12.

=16+1.

=17,

and tanθ=CyCx.

θ=tan-1-14=14∘.

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