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Chapter 16: Q. 39 (page 452)

A loudspeaker on a tall pole broadcasts sound waves equally in all directions. What is the speaker鈥檚 power output if the sound intensity level is 90 dB at a distance of 20 m?

Short Answer

Expert verified

The power output of the speaker is5W.

Step by step solution

01

Given information

The sound intensity level of the loudspeaker is 尾=90dB.

Distance isr=20m.

02

Power output of the speaker

The sound level intensity of the speaker is given by 尾=10dBlog10II0鈥�1.

The intensity of the sound wave is given by I=Pa鈥�2

From (1) and (2) we get,

P=IaP=I0脳10尾10dB脳4蟺谤2

Substitute the given values

P=1脳10-12脳1090dB10dB脳4蟺202P鈮�5W

Therefore, the power output of the speaker is5W.

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