91Ó°ÊÓ

In the microsystem, the potential energy between bonds is zero, and the kinetic energy of a monatomic gas is translational kinetic energy.. If the temperature changes by $\mathrm{Δ}T$, then the thermal energy for monatomic gas changes by equation $(20.34)$in the form

$\mathrm{Δ}{E}_{{\mathrm{th}}_{\mathrm{gas}}}=\frac{3}{2}nR\mathrm{Δ}{T}_{\mathrm{gas}}$

Where $n$is the number of moles and $R$is the universal gas constant.

If the temperature changes by $∆T$, then the thermal energy for solid changes by equation $(20.34)$in the form

$\mathrm{Δ}{E}_{{\mathrm{th}}_{\text{solid}}}=3nR\mathrm{Δ}{T}_{\text{solid}}$

When the gas interacts thermally with the solid, they reach the thermal equilibrium after time, so we can get an expression for $∆T_{soli{d}_{}}$when the number of moles is the same

$\mathrm{Δ}{E}_{{\mathrm{th}}_{\mathrm{gas}}}=\mathrm{Δ}{E}_{{\mathrm{th}}_{\text{solid}}}$

$\frac{3}{2}nR\mathrm{Δ}{T}_{\text{gas}}=3nR\mathrm{Δ}{T}_{\text{solid}}$

$\mathrm{Δ}{T}_{\text{solid}}=\frac{\mathrm{Δ}{T}_{\text{gas}}}{2}$

Now, we plug the values for $∆T_{gas}$into equation (3) to get $∆T_{solid}$

$\mathrm{Δ}{T}_{\text{solid}}=\frac{\mathrm{Δ}{T}_{\text{gas}}}{2}$

$=\frac{{50}^{∘}\mathrm{C}}{2}$

$={25}^{∘}\mathrm{C}$