/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 3 The wire is broken on the right ... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 29: Q. 3 (page 796)

The wire is broken on the right side of the circuit in FIGURE Q28.3. What is the potential difference V1-V2between points 1and2? Explain.

Short Answer

Expert verified

The potential difference between the two points is given by鈭�V12=3V

Step by step solution

01

Given information and formula used 

Given :

The wire is broken on the right side of the circuit in the given figure :

Theory used :

Ohm's law, description of the relationship between current, voltage, and resistance. The amount of steady current through a large number of materials is directly proportional to the potential difference, or voltage, across the materials.

02

Determining the potential difference between points 1 and 2

The resistor creates a voltage drop for the battery when the wire is connected, and the current flowing through the resistance is determined by Ohm's equation as I=3V3惟=1A

The current through the resistance is zero, that isI=0when the wire is broken, and there is no voltage drop for the battery.

Hence the two points 1and2have the same potential difference as the battery. So

鈭�V12=3V

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A conducting bar of length l and mass m rests at the left end of the two frictionless rails of length d in FIGURE P29.75. A uniform magnetic field of strength B points upward.

a. In which direction, into or out of the page, will a current through the conducting bar cause the bar to experience a force

to the right?

b. Find an expression for the bar鈥檚 speed as it leaves the rails at

the right end.

Find an expression for the magnetic field strength at the center (pointP)of the circular arc in FIGURE P29.45.

An electron moves in the magnetic fieldB鈬赌=0.50i^T with a speed of 1.0脳107m/sin the directions shown in FIGURE EX29.27. For each, what is magnetic force on the electron? Give your answers in component form.

a. An infinitely long sheet of charge of width L lies in the x y plane between x=-L / 2 and x=L / 2. The surface charge density is 畏. Derive an expression for the electric field E鈫� along the x-axis for points outside the sheet (x>L/2).

b. Verify that your expression has the expected behavior ifx鈮�L.

Hint: ln(1+u)鈮�uifu鈮�1.

c. Draw a graph of field strength E versus x for x>L / 2.

The 10-turn loop of wire shown in FIGURE P29.71 lies in a horizontal plane, parallel to a uniform horizontal magnetic field, and carries a 2.0 A current. The loop is free to rotate about a nonmagnetic axle through the center. A 50 g mass hangs from one edge of the loop. What magnetic field strength will prevent the loop from rotating about the axle?
See all solutions

Recommended explanations on Physics Textbooks

Circular Motion and Gravitation

Read Explanation

Nuclear Physics

Read Explanation

Fluids

Read Explanation

Magnetism

Read Explanation

Particle Model of Matter

Read Explanation

Dynamics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.