/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 28 Radio astronomers detect electro... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Radio astronomers detect electromagnetic radiation at 45 MHz from an interstellar gas cloud. They suspect this radiation is emitted by electrons spiraling in a magnetic field. What is the magnetic field strength inside the gas cloud?

Short Answer

Expert verified

The magnetic field strength inside the gas cloudB=1.61mT

Step by step solution

01

Introduction

The given is the Radio astronomers detect electromagnetic radiation at 45MHzfrom an interstellar gas cloud

The objective to find the magnetic field strength inside the gas cloud

The method used here is cyclotron motion to find the magnetic field

02

Step 1

The cyclotron motion is defined as a particle travelling in a uniform circular motion perpendicular to the magnetic field at a constant speed. The magnetic field causes the circular motion to produce a circular frequency, which is given by equation (29.21)in the form

fcyc=qB2Ï€³¾(1)

Where qdenotes the particle's charge, Bthe magnetic field, and mthe particle's mass. The frequency is determined by the magnetic field, not the particle's velocity, as indicated by equation (1). We rewrite equationdata-custom-editor="chemistry" (1)so that Bis in the form

B=2Ï€³¾fcycq(2)

03

Step 2

Now we plug in the electron's fcyc, m, and qvalues to get B.

role="math" localid="1648904991159" B=2Ï€³¾fcycq=2Ï€(9.1×10-31Kg)(45×106Hz)1.6×10-19C=1.61×10-3T=1.61mT

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

a. In FIGURE P29.76, a long, straight, current-carrying wire of linear mass density μis suspended by threads. A magnetic field perpendicular to the wire exerts a horizontal force that deflects the wire to an equilibrium angle θ. Find an expression for the strength and direction of the magnetic field B⇶Ä.

b. What B⇶Ädeflects a 55 g/m wire to a 12° angle when the current is 10 A?

Particle accelerators, such as the Large Hadron Collider, use magnetic fields to steer charged particles around a ring. Consider a proton ring with 36 identical bending magnets connected by straight segments. The protons move along a 1.0-m-long circular arc as they pass through each magnet. What magnetic field strength is needed in each magnet to steer protons around the ring with a speed of 2.5×107m/s ? Assume that the field is uniform inside the magnet, zero outside.

A wire carries current I into the junction shown in FIGURE EX29.13. What is the magnetic field at the dot?

The element niobium, which is a metal, is a superconductor (i.e., no electrical resistance) at temperatures below 9K. However, the superconductivity is destroyed if the magnetic field at the surface of the metal reaches or exceeds 0.10T. What is the maximum current in a straight,3mm diameter superconducting niobium wire?

To five significant figures, what are the cyclotron frequencies in a 3.0000Tmagnetic field of the ions (a)O2+, (b)N2+, and (c)CO+? The atomic masses are shown in the table; the mass of the missing electron is less than 0.001u and is not relevant at this level of precision. Although N2+and C2+both have a nominal molecular mass of 28, they are easily distinguished by virtue of their slightly different cyclotron frequencies. Use the following constants:1u=1.6605×10-27Kg,e=1.6022×10-19C.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.