/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 23 The value of the line integral o... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 29: Q. 23 (page 831)

The value of the line integral of B鈫�around the closed path in FIGURE EX29.23 is 1.38脳10-5T.m. What are the direction (in or out of the page) and magnitude of I3?

Short Answer

Expert verified

The current I3=23Aand it is points into the paper.

Step by step solution

01

Given information

We have given,

line integral =1.38脳10-5T.m

We have to find the current I3and its flow of direction.

02

Simplify

Using ampere's law, for any closed path is given by,

鈭�B鈫�.dS鈫�=渭0I

Where I is a total enclosed current in the magnetic field curve.

then total current will be

I=I2+I3I=-12A+I3.......................(1)

since other currents are out of closed curve.

since,

鈭�B鈫�.dS鈫�=渭0I鈭�B鈫�.dS鈫�=(4蟺脳10-7T.m/A)II=鈭�B鈫�.dS鈫�4蟺脳10-7=1.38脳10-5T.m4脳3.14脳10-7T.m/AI=11A

using equation (1),

localid="1649421657359" I=11A=-12A+I3I3=23A.

the positive sine indicates that current will be into the paper.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Find an expression for the magnetic field strength at the center (point P) of the circular arc in FIGUREP29.45.

FIGUREP29.45 localid="1649251364548" FIGUREP29.46

What is the magnetic field strength at the center of the semicircle in figureP29.54?

The two10cmlong parallel wires in FIGURE EX29.34 are separated by 5.0mm. For what value of the resistor R will the force between the two wires be 5.4脳10-5N?

significant figures, what are the cyclotron frequencies in a magnetic field of the ions (a)O2+, (b)N2+and (c)CO+? The atomic masses are shown in the table; the mass of the missing electron is less than 0.001uand is not relevant at this level of precision. Although N7+andCO+both have a nominal molecular mass of 28, they are easily distinguished by virtue of their slightly different cyclotron frequencies. Use the following constants:1u=1.6605脳10鈭�27kg,ee=1.6022脳10鈭�19C.

The element niobium, which is a metal, is a superconductor (i.e., no electrical resistance) at temperatures below 9K. However, the superconductivity is destroyed if the magnetic field at the surface of the metal reaches or exceeds 0.10T. What is the maximum current in a straight,3mm diameter superconducting niobium wire?
See all solutions

Recommended explanations on Physics Textbooks

Famous Physicists

Read Explanation

Work Energy and Power

Read Explanation

Classical Mechanics

Read Explanation

Mechanics and Materials

Read Explanation

Fundamentals of Physics

Read Explanation

Nuclear Physics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.