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The earth’s magnetic dipole moment is 8.0×1022A.m2.

a. What is the magnetic field strength on the surface of the earth at the earth’s north magnetic pole? How does this compare to the value in Table 29.1? You can assume that the current loop is deep inside the earth.

b. Astronauts discover an earth-size planet without a magnetic field. To create a magnetic field at the north pole with the same strength as earth’s, they propose running a current through a wire around the equator. What size current would be needed?

Short Answer

Expert verified

a. The magnetic field is 61.8μ°Õ.

b. current is6.3×108A.

Step by step solution

01

Part (a) Step 1: Given information

We have given,

magnetic moment = 8×1022A.m2

we have to find the magnetic field at north pole.

02

Simplify

The magnetic field due to dipole

B=μ0μ→2Ï€°ù3B=(4π×10-7)(8×1022)2Ï€(6.4×106)3B=61.8μ°Õ

03

Part (b) Step 1: Given information

We have given,

magnetic dipole moment = 8×1022A.m2

We have to find the current needed.

04

Simplify

The magnetic dipole moment due to loop is

μ→=A.II=μ→πr2I=8×1022π(6.4×106)2I=6.3×108A

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