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Through what potential difference would you need to accelerate an alpha particle, starting from rest, so that it will just reach the surface of a 15-fm-diameter 238U nucleus?

Short Answer

Expert verified

The potential difference with which we need to accelerate the alpha particle is1.766×107V

Step by step solution

01

Step 1. Given information is :Nucleus is of 238UDiameter = 15 fm

We need to find out the potential difference with which we need to accelerate the alpha particle so that it will just reach the surface of a 15-fm-diameter238U nucleus

02

Step 2. Using Conservation of energy

Kinitial+Uinitial=Kfinal+UfinalUinitial=0Ufinal=14π∈oq1q2rUfinal=14π∈o(2e)(92e)rKfinal=0Puttingvalues,Kinitial+0=0+UfinalKinitial=14π∈o(2e)(92e)rKinitial=q∆V∆V=Kinitialqq=2eforalphaparticle∆V=Kinitial2e∆V=14π∈o(2e)(92e)r2e=14π∈o(92e)r∆V=9×109×92×1.6×10-197.5×10-15∆V=1.766×107V

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