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Chapter 37: Q. 24 (page 1082)

Consider the lead isotope 207Pb.

a. How many electrons, protons, and neutrons are in a neutral207Pbatom?

b. The lead nucleus has a diameter of 14.2fm. What is the electric field strength at the surface of a lead nucleus?

Short Answer

Expert verified

a. In neutral P207bnumber of neutrons are125, number of protons are 82and the number of electrons are82.

b. The electric field strength at the surface of the nucleus is(2.34脳1021)NC.

Step by step solution

01

Part (a) step 1: Given information 

We have to find that How many electrons, protons, and neutrons are in a neutral 207Pbatom.

02

Part (a) step 2: Simplify 

Start the solution by determining the proton number:

Z=82 (from Periodic Table of Elements)

A=Z+N

N=A-Z

Putting the values

N=207-82=125

Here, Zis the atomic number, A is the mass number and N is the neutron number.

03

Part (b) step 1: Given information 

We have to find that the electric field strength at the surface of a lead nucleus.

04

Part (b) step 2: Simplify 

The expression for the electric field of the point charge:

E=Q4蟺鈭�0r2E=(82)路e4蟺鈭�0(7.1脳10-15)2E=(2.34脳1021)NC

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