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Chapter 37: Given Information (page 1081)

11. An alpha particle (a bare helium nucleus with q=+2e) accelerates across a 100V potential difference, starting from rest. What is the particle鈥檚 kinetic energy in eV when it reaches the negative electrode? This question requires no mathematics beyond what you can do in your head.

Short Answer

Expert verified

As, We know

KE=qV

So, by putting given values into the equation:

KE= 100x2 =200 eV

Step by step solution

01

Description

The formula for energy in terms of charge and potential difference is

Kinetic energy = potential difference x charge

KE=qV

So, by putting given values of charge q=+2e

And, Potential difference between the plates V=100Volt

into the equation:

KineticEnergy=2e脳100V=200eV

So, the particle鈥檚 kinetic energy when it reaches the negative electrode is

200eV.

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