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Chapter 25: Q. 8 (page 709)

Two positive point charges are5.0cm apart. If the electric potential energy is72渭闯 , what is the magnitude of the force between the two charges?

Short Answer

Expert verified

The force between the two charges has a magnitude of1.4脳10-3N.

Step by step solution

01

Formula for magnitude of force

Given information:

Distance between two positive charges is 5.0cm.

Electric potential energy is 72渭J.

Find:

The objective is to find magnitude of the force between two charges.

The potential energy is calculated as follows:

U=14蟺蔚0Q1Q2r..1

when the force's magnitude is

F=14蟺蔚0Q1Q2r2.......2

Q1-Charge of point 1

Q2-Charge of point 2

r-Distance

U-Electric potential energy

02

Calculation for magnitude of force

when the force's magnitude is

F=14蟺蔚0Q1Q2r2

Equation2divided by equation1,

we obtain,

FU=1r21r=1r

This results in

F=1rU

=72渭闯5.0cm

localid="1649412963669" =1.4脳10-3N

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ReproduceFIGUREQ25.12on your paper. Then draw a dot (or dots) on the figure to show the position (or positions) at which the electric potential is zero.

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