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Chapter 25: Q. 71 (page 713)

FIGURE P25.71 shows a thin rod with charge Q that has been bent into a semicircle of radius R. Find an expression for the electric potential at the center.

Short Answer

Expert verified

The electric potential as the center iskQR.

Step by step solution

01

Given Information

We need to find an expression for the electric potential at the center.

02

Explanation

Let us consider that if we have more than one point, the potential can be written as

V=k鈭�qr.

In this case, one might first thing we need to integrate, but in fact we can't, as all the charge parts, however we split them, are equally distant from the point of interest. That is, we have

V=kR鈭�qV=kQR

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Most popular questions from this chapter

FIGURE EX 25.10 shows the potential energy of an electric dipole. Consider a dipole that oscillates between卤60掳.

a. What is the dipole's mechanical energy?

b. What is the dipole's kinetic energy when it is aligned with the electric field?

What is the electric potential at the point indicated a dot in FIGURE EX25.31?

A 2.0-mm-diameter glass bead is positively charged. The potential difference between a point 2.0 mm from the bead and a point 4.0 mm from the bead is 500 V. What is the charge on the bead?

Two 2.00cm脳2.00cm plates that form a parallel-plate capacitor are charged to 0.708 nC. What are the electric field strength inside and the potential difference across the capacitor if the spacing between the plates is (a) 1.00 mm and (b) 2.00 mm?

A capacitor with plates separated by distance dis charged to a potential difference 鈭�VC. All wires and batteries are disconnected, then the two plates are pulled apart (with insulated handles) to a new separation of distance2d.
a. Does the capacitor chargeQ change as the separation increases?
If so, by what factor? If not, why not?
b. Does the electric field strengthEchange as the separation increases? If so, by what factor? If not, why not?
c. Does the potential difference 鈭�VCchange as the separation increases? If so, by what factor? If not, why not?
See all solutions

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