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An arrangement of source charges produces the electric potential V = 5000x2 along the x-axis, where V is in volts and x is in meters. What is the maximum speed of a 1.0 g, 10 nC charged particle that moves in this potential with turning points at 8.0 cm?

Short Answer

Expert verified

The value of maximum speed of a 1.0 g, 10 n C charged particle 2.53 cm/s

Step by step solution

01

The theory of the maximum speed of a  charged particle 

The potential energy as potential function is as follows;

U=qV

Now the expression of potential is;

U(x)=5000qx2

There is no potential energy, all energy here is potential. Thus after application law of energy conversion;

U=mv22v=2Um

02

Formulation of kinetic energy

The value of maximum speed of a 1.0 g, 10 n C charged particle

v(x)=104qx2m

After substituting all the values speed of particle is;

v=10410-80.0820.001=0.025m/s

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