/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 45 An arrangement of source charges... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 25: Q. 45 (page 711)

An arrangement of source charges produces the electric potential V = 5000x2 along the x-axis, where V is in volts and x is in meters. What is the maximum speed of a 1.0 g, 10 nC charged particle that moves in this potential with turning points at 8.0 cm?

Short Answer

Expert verified

The value of maximum speed of a 1.0 g, 10 n C charged particle 2.53 cm/s

Step by step solution

01

The theory of the maximum speed of a  charged particle 

The potential energy as potential function is as follows;

U=qV

Now the expression of potential is;

U(x)=5000qx2

There is no potential energy, all energy here is potential. Thus after application law of energy conversion;

U=mv22v=2Um

02

Formulation of kinetic energy

The value of maximum speed of a 1.0 g, 10 n C charged particle

v(x)=104qx2m

After substituting all the values speed of particle is;

v=104脳10-8脳0.0820.001=0.025m/s

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

FIGUREQ25.2shows the potential energy of a proton q=+eand a lead nucleusq=+82e. The horizontal scale is in units of femtometers, where 1fm=10-15m.

aA proton is fired toward a lead nucleus from very far away. How much initial kinetic energy does the proton need to reach a turning point10fm from the nucleus? Explain.
bHow much kinetic energy does the proton of part a have when it is20fmfrom the nucleus and moving toward it, before the collision?

What is the speed of an electron that has been accelerated from rest through a potential difference of 1000V?

What is the potential energy of the electron-proton interactions in FIGURE EX25.5? The electrons are fixed and cannot move.

What potential difference is needed to accelerate an electron from rest to a speed of 2.0脳106m/s?

Show that 1 V/m = 1 N/C.
See all solutions

Recommended explanations on Physics Textbooks

Radiation

Read Explanation

Energy Physics

Read Explanation

Solid State Physics

Read Explanation

Circular Motion and Gravitation

Read Explanation

Electric Charge Field and Potential

Read Explanation

Medical Physics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.