91Ó°ÊÓ

The electric potential equation of a dot points

$V=\frac{1}{4\mathrm{Ï€}{\mathrm{Î\mu }}_0}\frac{q}{r}$

where the q is the charge points, r is the distance and ${\mathrm{Î\mu }}_0$permittivity free space

For the multiple Points $\underset{i}{∑}{V}_i=\frac{1}{4\mathrm{Ï€}{\mathrm{Î\mu }}_0}\frac{q_i}{r_i}$

From the given triangle, all distances from O to other points A, B, C are equal.

Due to these facts,$OA=OB=OC$

$OA=OB=OC$

Now, the length of the bc is equal to

$\begin{array}{rcl}\frac{1}{2}AC& =& \frac{1}{2}(3.0)cm\\ & =& 1.5cm\end{array}$

On the basis of the right-angle triangle

the length of

$\begin{array}{rcl}OC& =& \frac{bC}{\cos ∠ObC}\\ & =& \frac{1.5cm}{\cos ∠30°}\\ & =& 1.7×{10}^{-2}\\ & & \end{array}$

The Value of the Electric Potential of the dot point is

$1.7×{10}^{-2}$

The electric potential equation of a dot points

$V=\frac{1}{4\mathrm{Ï€}{\mathrm{Î\mu }}_0}\frac{q}{r}$

where the q is the charge points, r is the distance and${\mathrm{Î\mu }}_0$ permittivity free space

For the multiple Points$\underset{i}{∑}{V}_i=\frac{1}{4\mathrm{Ï€}{\mathrm{Î\mu }}_0}\frac{q_i}{r_i}$

From the given triangle, all distances from O to other points A, B, C are equal.

Due to these facts,$OA=OB=OC$