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A 3.0-cm-diameter parallel-plate capacitor has a 2.0 mm

1.0×105V/mspacing. The electric field strength inside the capacitor is.

a. What is the potential difference across the capacitor?

b. How much charge is on each plate?

Short Answer

Expert verified

a. the value of electrical potential is 200 V.

b. the charge value on each plate is6.3×10-10C

Step by step solution

01

Definition of  parallel-plate capacitor

The equation of electric potential inside a parallel plate is E=V×d

Now here;

E=1.0×105V/md=2.0×10-3mHenceV=(1.0×105V/m)×(2.0×10-3m)=200V


02

 Charge of  the parallel  plate  

The charge of the each plate equation;

Q=πr2ε0Vcd

role="math" localid="1648304281271" Here;Vc=3.14r=1.5×10-2mε0=8.85×10-12C2/Nm2π=2.0×10-3m

Therefore , the value of

Q=3.141.5×10-2m8.85×10-12C2/Nm2200V2.0×10-3m=6.3×10-10C

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Most popular questions from this chapter

FIGUREQ25.11shows three points near two point charges. The charges have equal magnitudes. For each part, rank in order, from most positive to most negative, the potentials Vato Vc.

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