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Chapter 25: Q. 17 (page 709)

Through what potential difference must a proton be accelerated to reach the speed it would have by falling 100min vacuum?

Short Answer

Expert verified

The potential difference by which the proton is to be accelerated is鈭�V=1.02脳10-5volts

Step by step solution

01

Given information and theory used 

Given : Proton falls : 100min vacuum

Theory used :

From the equation of conservation of energy, we have :mgh=q鈭�V

02

calculating the potential difference by which the proton is to be accelerated.

A proton will have an energy of mghif it falls in vacuum from a height of h

Rewriting rule of conservation of energy we have :

鈭�V=mghq

In terms of numbers, we have

鈭�V=1.67脳10-27脳9.81脳1001.6脳10-19=1.02脳10-5volts

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