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Chapter 23: Q. 72 (page 657)

A proton orbits a long charged wire, making 1.0脳106 revolutions per second. The radius of the orbit is 1.0cm. What is the wire鈥檚 linear charge density?

Short Answer

Expert verified

The wire鈥檚 linear charge density is-2.28nC/m

Step by step solution

01

Given information and Formula used

Given :

Proton makes revolutions per second : 1.0脳106

The radius of the orbit : 1.0cm

Theory used :

Electric field due to long charged wire at distance r

E=2位4蟺蔚0r

(Electrostatic force is attractive, therefore 位is negative.)

The proton receives centripetal force from electrostatic force, that isFc=Fe

02

Calculating the wire’s linear charge density 

Now, PE=mw2r

Using the above relation, we can deduce :

-2位脳e2蟺蔚0r=mw2r鈬�-位=1.67脳10-27脳(2蟺脳106)2脳(10-2)22脳1.6脳10-19脳9脳109=-2.28x109C/m鈬�位=-2.28nC/m

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Most popular questions from this chapter

The electric field strength 10.0cmfrom a very long charged wire is 2000N/C. What is the electric field strength 5.0cm from the wire?

You鈥檝e been assigned the task of determining the magnitude and direction of the electric field at a point in space. Give a step-by-step procedure of how you will do so. List any objects you will use, any measurements you will make, and any calculations you will need to perform. Make sure that your measurements do not disturb the charges that are creating the field.

The two parallel plates in FIGURE P23.53are 2.0cmapart and the electric field strength between them is 1.0脳104N/C. An electron is launched at a 45鈭� angle from the positive plate. What is the maximum initial speed v0 the electron can have without hitting the negative plate?

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The electric field 5.0cmfrom a very long charged wire is (2000 N/C, toward the wire). What is the charge (in nC) on a1.0-cm-long segment of the wire?
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