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A thin cylindrical shell of radius Rand length L, like a soda straw, is uniformly charged with surface charge density η. What is the electric field strength at the center of one end of the cylinder?

Short Answer

Expert verified

The electric field strength at the center of one end of the cylinder isη2ε0[1-RL2+R2]

Step by step solution

01

Given information and formula used

Given :

Cylindrical shell has radius and length : RandLrespectively.

It is uniformly charged with surface charge density : η

Theory used :

Charge on the cylinder is by:

η=QA=Q2πRL⇒Q=2πRLη(WhereisA=2πRL.)
For all rings, use this formula:

Er=dE=14πε03dq(z2+R)3/2

02

Finding the electric field strength at the center of one end of the cylinder.

Now we integrate Er=dE:

role="math" localid="1649488487347" Ec=∫dE=14πε0∫0Lzdq(z2+R)3/2=14πε0∫0L2πRηzdz(z2+R)3/2=Rη2ε0-1z2+R20L=Rη2ε0[-1L2+R2--1R]=η2ε0[1-RL2+R2]

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