/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q10. A trumpet player hears 5 beats p... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A trumpet player hears 5 beats per second when she plays a note and simultaneously sounds a 440 Hz tuning fork. After pulling her tuning valve out to slightly increase the length of her trumpet, she hears 3 beats per second against the tuning fork. Was her initial frequency 435 Hz or 445 Hz? Explain.

Short Answer

Expert verified

445Hz

Step by step solution

01

Given Information

A trumpet is played alongside a tuning fork of 440Hz and beat frequency is 5Hz

Then length of trumpet is increased and so beat frequency is decreased to 3Hz.

02

Applying the formula for beat frequency

fs-ft=fb

Where, fs is frequency of source (in this case trumpet)

ft is frequency of tuning fork, (in this case 440Hz)

fb is frequency of beats (in this case 5Hz)

03

Putting the values

fs-440Hz=5Hz⇒fs=445Hz/435Hz

So there are two possible values of frequency of trumpet, i.e. 445Hz or 435Hz.

04

Increase in wavelength

Now it is given that when we slightly increased the length of the pipe, i.e. we increased the wavelength (decreased the frequency of trumpet) beat frequency is dropped to 3Hz. This means that initial frequency is higher that frequency of tuning fork. Therefore we get that initial frequency of trumpet was 445Hz.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Engineers are testing a new thin-film coating whose index of refraction is less than that of glass. They deposit a 560-nm-thick layer on glass, then shine lasers on it. A red laser with a wavelength of 640 nm has no reflection at all, but a violet laser with a wavelength of 400 nm has a maximum reflection. How the coating behaves at other wavelengths is unknown. What is the coating’s index of refraction?

A heavy piece of hanging sculpture is suspended by a 90-cmlong, 5.0 g steel wire. When the wind blows hard, the wire hums at its fundamental frequency of 80 Hz. What is the mass of the sculpture?

A metal wire under tension T0 vibrates at its fundamental

frequency. For what tension will the second-harmonic frequency

be the same as the fundamental frequency at tension T0?

A soap bubble is essentially a very thin film of water 1n = 1.332 surrounded by air. The colors that you see in soap bubbles are produced by interference.

a. Derive an expression for the wavelengths lC for which constructive interference causes a strong reflection from a soap bubble of thickness d. Hint: Think about the reflection phase shifts at both boundaries.

b. What visible wavelengths of light are strongly reflected from a 390-nm-thick soap bubble? What color would such a soap bubble appear to be?

Standing waves on a 1.0-m-long string that is fixed at both ends are seen at successive frequencies of 36 Hz and 48 Hz. a. What are the fundamental frequency and the wave speed? b. Draw the standing-wave pattern when the string oscillates at 48 Hz.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.