/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 40 A particularly beautiful note re... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 17: Q. 40 (page 485)

A particularly beautiful note reaching your ear from a rare Stradivarius violin has a wavelength of 39.1 cm. The room is slightly warm, so the speed of sound is 344 m/s. If the string鈥檚 linear density is 0.600 g/m and the tension is 150 N, how long is the vibrating section of the violin string?

Short Answer

Expert verified

The length of the string is 0.28 m

Step by step solution

01

Write the given information 

Wavelength of the wave, 位 = 39.1 cm = 0.391 m
The speed of sound, v = 344 m/s
The linear density of the string, 碌 = 0.600 g/m = 0.600 x 10-3 kg/m
Tension in the string, T= 150 N

02

 Step 2: To determine the length of the string

The frequency of the wave is given by
f=v位f=3440.391f=879.7Hz

The expression for the fundamental frequency of the string wave is given by
f=12LT碌879.7=12L1500.6x10-3879.7=12L5x102L=250879.7L=0.28m

Thus, the length of the string is 0.28 m

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

|| The three identical loudspeakers

in FIGURE P17.71 play a 170 Hz tone

in a room where the speed of sound

is 340 m/s. You are standing 4.0 m

in front of the middle speaker. At

this point, the amplitude of the wave

from each speaker is a.

a. What is the amplitude at this

point?

b. How far must speaker 2 be moved

to the left to produce a maximum

amplitude at the point where you

are standing?

c. When the amplitude is maximum,

by what factor is the sound intensity

greater than the sound intensity from a single speaker?

A flutist assembles her flute in a room where the speed of

sound is 342 m/s. When she plays the note A, it is in perfect tune

with a 440 Hz tuning fork. After a few minutes, the air inside her

flute has warmed to where the speed of sound is 346 m/s.

a. How many beats per second will she hear if she now plays the

note A as the tuning fork is sounded?

A 2.0-m-long string vibrates at its second-harmonic frequency with a maximum amplitude of 2.0 cm. One end of the string is at x = 0 cm. Find the oscillation amplitude at x = 10, 20, 30, 40, and 50 cm.

You have two small, identical boxes that generate 440 Hz

notes. While holding one, you drop the other from a 20-m-high

balcony. How many beats will you hear before the falling box hits

the ground? You can ignore air resistance.

A steel wire is used to stretch the spring of FIGURE P17.42. An oscillating magnetic field drives the steel wire back and forth. A standing wave with three antinodes is created when the spring is stretched 8.0 cm. What stretch of the spring produces a standing wave with two antinodes?
See all solutions

Recommended explanations on Physics Textbooks

Physical Quantities And Units

Read Explanation

Oscillations

Read Explanation

Electromagnetism

Read Explanation

Kinematics Physics

Read Explanation

Electrostatics

Read Explanation

Force

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.