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14. II The four masses shown in FIGURE EX12.13 are connected by massless, rigid rods.

a. Find the coordinates of the center of mass.

b. Find the moment of inertia about a diagonal axis that passes through masses B and D.

Short Answer

Expert verified

a. The center of mass (x,y) is ( 0.0625, 0.050 )m

b. The moment of inertia about a diagonal is0.00163kgm2

Step by step solution

01

Part (a)

The center of mass x-component

xcm=∑mixi∑mi=mAxA+mBxB+mCxC+mDxDmA+mB+mC+mDxcm=(100g)(0m)+(200g)(0m)+(300g)(0.10m)+(200g)(0.10m)100g+200g+300g+200gxcm=0.0625m

The center of mass y-component

ycm=∑miyi∑mi=mAyA+mByB+mCyC+mDyDmA+mB+mC+mDycm=(100g)(0m)+(200g)(0.08m)+(300g)(0.08cm)+(200g)(0m)100g+200g+300g+200gycm=0.05m

02

Part (b)

The length of the diagonal is,

d=(10cm)2+(8cm)2=12.8cm

The distance at point and point is

r=d2r=12.8cm2=6.4cmrA=rC=6.4cm

As the axis is passing through the and , so, the distance at point and is zero.

rB=rD=0

The moment of inertia about a diagonal that passes through B and D is

IBD=mArA2+mCrC2 + mBrB2+mDrD2IBD=(0.100kg)0.064″¾2+(0.300kg)0.064″¾2+0+0IBD=0.00163kgm2

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