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The nuclear reaction that powers the sun is the fusion of four protons into a helium nucleus. The process involves several steps, but the net reaction is simply 4pHe4+Energy. The mass of a proton, to four significant figures, is 1.67310-27kg, and the mass of a helium nucleus is known to be 6.64410-27kg.

a. How much energy is released in each fusion?

b. What fraction of the initial rest mass energy is this energy?

Short Answer

Expert verified

a. The energy will released is E=4.1410-22J.

b. fraction percentage is0.68%.

Step by step solution

01

Part (a) Step 1: Given information

We have given,

reaction,

4pHe4+Energy

Mass of proton =1.67310-27kg

Mass of helium =6.64410-27kg

02

Simplify 

The mass difference is ,

m=(41.67310-27kg)-(6.64410-27kg)m=0.04810-27kg

Then, the energy will be,

E=mc2E=(0.04810-27kg)(3108)2 E=4.1410-22J

03

Part 9b) Step 1: Given information

We have given,

Mass of proton =1.67310-27kg

Mass of Helium =6.64410-27kg

We have to find the fraction of the initial rest mass energy.

04

Simplify

The initial rest mass energy is ,

4penergy=41.67310-27kgc2

Then the fraction will be,

localid="1649944799947" fraction%=E4penergy100fraction%=0.04810-27kg41.67310-27kg100fraction=0.68%

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