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Chapter 36: Q. 71 (page 1062)

The nuclear reaction that powers the sun is the fusion of four protons into a helium nucleus. The process involves several steps, but the net reaction is simply 4p鈫�He4+Energy. The mass of a proton, to four significant figures, is 1.673脳10-27kg, and the mass of a helium nucleus is known to be 6.644脳10-27kg.

a. How much energy is released in each fusion?

b. What fraction of the initial rest mass energy is this energy?

Short Answer

Expert verified

a. The energy will released is E=4.14脳10-22J.

b. fraction percentage is0.68%.

Step by step solution

01

Part (a) Step 1: Given information

We have given,

reaction,

4p鈫�He4+Energy

Mass of proton =1.673脳10-27kg

Mass of helium =6.644脳10-27kg

02

Simplify 

The mass difference is ,

鈭�m=(4脳1.673脳10-27kg)-(6.644脳10-27kg)鈭�m=0.048脳10-27kg

Then, the energy will be,

E=鈭�mc2E=(0.048脳10-27kg)(3脳108)2 E=4.14脳10-22J

03

Part 9b) Step 1: Given information

We have given,

Mass of proton =1.673脳10-27kg

Mass of Helium =6.644脳10-27kg

We have to find the fraction of the initial rest mass energy.

04

Simplify

The initial rest mass energy is ,

4penergy=4脳1.673脳10-27kg脳c2

Then the fraction will be,

localid="1649944799947" fraction%=E4penergy脳100fraction%=0.048脳10-27kg4脳1.673脳10-27kg脳100fraction=0.68%

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Most popular questions from this chapter

Teenagers Sam and Tom are playing chicken in their rockets. As FIGURE Q36.2 shows, an experimenter on earth sees that each is traveling at 0.95cas he approaches the other. Sam fires a laser beam toward Tom.

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