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At what speed, as a fraction of c, is a particle鈥檚 total energy twice its rest energy?

Short Answer

Expert verified

The speed of particle is 0.866c.

Step by step solution

01

Given information

We have given that, particle鈥檚 total energy twice its rest energy.

02

Step 1.

We know that the formula of total energy is :

E=pmc2

Here, m = mass of particle

v = velocity of particle

p= Lorentz factor

We have given that total energy is twice of rest mass energy.

E=2E0

Here E= total energy

E0= rest mass energy

03

Step 2.

Substituting E=2E0in the formula of total energy :

2mc2=pmc2

p=2

We know that p=11-v2c2, substituting this value of p:

11-v2c2=2

v2c2=34

v=0.866c

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