Q. 8 A converging lens creates the im... [FREE SOLUTION]

Chapter 34: Q. 8 (page 989)

A converging lens creates the image shown in FIGURE Q34.8. Is the object distance less than the focal length f, between f and 2 f, or greater than 2 f? Explain

Short Answer

Expert verified

The object is between f and 2f away.

Step by step solution

Find f:

When we have a converging lens and the image is inverted, real, and magnified (as shown in figure Q34.8), the object is backslash boxed backslash backslash text between f and 2 f away from the lens. Remember the thin lens equation?

$\frac{1}{f} = \frac{1}{s} + \frac{1}{s^{鈥�}}$

we get

$\frac{1}{s^{鈥�}} = \frac{1}{f} 鈭� \frac{1}{s} .$

Find 2f or greater thean 2f

Since $s > f$ then $\frac{1}{f} > \frac{1}{s}$ i.e. we see that $s^{'}$ is positive meaning the image is real and on the other side of the lens (as is the case in this problem). Also, $s < 2 f$ means that $\frac{1}{s} > \frac{1}{2 f}$ i.e. $\frac{1}{f} - \frac{1}{s} < \frac{1}{f} - \frac{1}{2 f} = \frac{1}{2 f}$ . Therefore

$\frac{1}{s^{鈥�}} < \frac{1}{2 f}$

yielding

So we got that only when f<s<2 f then $s^{'} > 2 f$ i.e. $s^{'} > s$ and the image is also magnified magnified.

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91影视

A converging lens creates the image shown in FIGURE Q34.8. Is the object distance less than the focal length f, between f and 2 f, or greater than 2 f? Explain

Short Answer

Step by step solution

Find f:

Find 2f or greater thean 2f

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