Chapter 34: Q 51 (page 992)
A 4.0-m-wide swimming pool is filled to the top. The bottom of the pool becomes completely shaded in the afternoon when the sun is 20° above the horizon. How deep is the pool?
Short Answer
The depth of the pool is 4.0 m
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Chapter 34: Q 51 (page 992)
A 4.0-m-wide swimming pool is filled to the top. The bottom of the pool becomes completely shaded in the afternoon when the sun is 20° above the horizon. How deep is the pool?
The depth of the pool is 4.0 m
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A -thick layer of oil is sandwiched between a thick sheet of glass and a -thick sheet of polystyrene plastic. How long (in ns) does it take light incident perpendicular to the glass to pass through this -thick sandwich?
Consider one point on an object near a lens.
a. What is the minimum number of rays needed to locate its image point? Explain.
b. How many rays from this point actually strike the lens and refract to the image point?
A concave mirror brings the sun's rays to a focus in front of the mirror. Suppose the mirror is submerged in a swimming pool but still pointed up at the sun. Will the sun's rays be focused nearer to, farther from, or at the same distance from the mirror? Explain.
A 2.0-cm-tall candle flame is 2.0 m from a wall. You happen to have a lens with a focal length of 32 cm. How many places can you put the lens to form a well-focused image of the candle flame on the wall? For each location, what are the height and orientation of the image?
3. One problem with using optical fibers for communication is that a light ray passing directly down the center of the fiber takes less time to travel from one end to the other than a ray taking a longer, zig-zag path. Thus light rays starting at the same time but traveling in slightly different directions reach the end of the fiber at different times. This problem can be solved by making the refractive index of the glass change gradually from a higher value in the center to a lower value near the edges of the fiber. Explain how this reduces the difference in travel times.
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