Chapter 34: Q. 39 (page 991)
An object is in front of a concave mirror with a focal length of . Use ray tracing to locate the image. Is the image upright or inverted?
Short Answer
The picture is behind the mirror, upright, and at a distance of
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Chapter 34: Q. 39 (page 991)
An object is in front of a concave mirror with a focal length of . Use ray tracing to locate the image. Is the image upright or inverted?
The picture is behind the mirror, upright, and at a distance of
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Suppose you have two pinhole cameras. The first has a small round hole in the front. The second is identical except it has a square hole of the same area as the round hole in the first camera. Would the pictures taken by these two cameras, under the same conditions, be different in any obvious way? Explain.
A tall candle flame is from a lens with a focal length of . What are the image distance and the height of the flame's image?
3. One problem with using optical fibers for communication is that a light ray passing directly down the center of the fiber takes less time to travel from one end to the other than a ray taking a longer, zig-zag path. Thus light rays starting at the same time but traveling in slightly different directions reach the end of the fiber at different times. This problem can be solved by making the refractive index of the glass change gradually from a higher value in the center to a lower value near the edges of the fiber. Explain how this reduces the difference in travel times.
A 25 g rubber ball is dropped from a height of 3.0 m above the center of a horizontal, concave mirror. The ball and its image coincide 0.65 s after the ball is released. What is the mirror’s radius of curvature?
A lens placed in front of an object creates an upright image twice the height of the object. The lens is then moved along the optical axis until it creates an inverted image twice the height of the object. How far did the lens move?
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