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A point source of light illuminates an aperture 2.0maway. A 12.0-cm-wide bright patch of light appears on a screen 1.0mbehind the aperture. How wide is the aperture?

Short Answer

Expert verified

The aperture width,x=8.0cm

Step by step solution

01

The ray model of light

The Ray Structure of Light: Light passes at v=c/nvia neat lines called light ray. The light ray will persist indefinitely except if it interacts with substance, in which case it will reflects, refract, disperse, or be consumed. Light rays are emitted by things. Rays are sent out in every dimensions from every spot on the item. When divergent rays are gathered either by pupil and centered just on retina, the person perceives an item (or a picture). If lens, reflectors, and apertures are bigger over 1mm, ray optics is acceptable.

02

Data given

2.0mis the spacing in between the aperture and point.

12.0cmis the width of the brilliant spot of light upon that screen.

1.0mis the distance seen between aperture and the display.

03

Width of the aperture

Lets xhave been the aperture's width. Its luminous area and aperture width are connected by, as seen by the identical triangles as in picture under.

12.0cm1.0m+2.0m=x2.0m

Calculate forx

x=(12.0cm)(2.0m)1.0m+2.0m

x=8.0cm

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Most popular questions from this chapter

A fortune teller鈥檚 鈥渃rystal ball鈥 (actually just glass) is 10 cm in diameter. Her secret ring is placed 6.0 cm from the edge of the ball.

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Use the best-fit line of an appropriate graph to determine the focal length of the lens.

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