/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 42 聽Use the on-axis potential of a... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 26: Q. 42 (page 739)

Use the on-axis potential of a charged disk from Chapter 25 to find the on-axis electric field of a charged disk

Short Answer

Expert verified

The electric field of charged disk isE(z)=-Q2蟺鈭�0R2zR2+z2-1

Step by step solution

01

Given information

We need to find the on-axis electric field of a charged disk

02

Simplify

The potential on the axis of a disk with charge Qand radius Rat distance zfrom it is given as

V(z)=Q2蟺鈭�0R2R2+z2-z.

The formula for electric field is

E=-dVdr,

Where ris the direction in which we're investigating the electric field. We have to take the negative of the derivative of the first expression with respect to z. It is given as

E=-dVdz=-Q2蟺鈭�0R2ddzR2+z2-z

If we perform the calculation correctly we get

E(z)=-Q2蟺鈭�0R2zR2+z2-1

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The electric potential in a region of uniform electric field is-1000V at x=-1.0m and +1000Vatx=+1.0m. What is Ex?

A 2.0cm-diameter parallel-plate capacitor with a spacing of 0.50mmis charged to 200V. What are

(a) the total energy stored in the electric field and

(b) the energy density?

You need a capacitance of 50mF, but you don鈥檛 happen to have a 50mFcapacitor. You do have a 75mFcapacitor. What additional capacitor do you need to produce a total capacitance of 50mF? Should you join the two capacitors in parallel or in series?

The parallel-plate capacitor in Figure Q26.11 is connected to a battery having potential difference 鈭�Vbat. Without breaking any of the connections, insulating handles are used to increase the plate separation to 2d.

a. Does the potential difference 鈭�VCchange as the separation increases? If so, by what factor? If not, why not?

b. Does the capacitance change? If so, by what factor? If not, why not?

c. Does the capacitor charge Qchange? If so, by what factor? If not, why not?

An electron is released from rest atx=2m in the potential shown in Figure Q26.6. Does it move? If so, to the left or to the right? Explain.
See all solutions

Recommended explanations on Physics Textbooks

Radiation

Read Explanation

Engineering Physics

Read Explanation

Rotational Dynamics

Read Explanation

Electric Charge Field and Potential

Read Explanation

Astrophysics

Read Explanation

Dynamics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.