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Chapter 15: Q.9 - Excercises And Problems (page 415)

An object in simple harmonic motion has an amplitude of 4.0cm, a frequency of 2.0Hz,and a phase constant of 2蟺/3rad.Draw a position graph showing two cycles of the motion.

Short Answer

Expert verified

position graph as follow

Step by step solution

01

Given information

amplitude a=4.0cm

frequency f=2.0Hz

phase constant胃=2蟺3rad

02

Explanation

The wave equation is in the form

x=acos蝇t+胃

The angular frequency is in the form

蝇=2蟺蹿=4蟺rad/s

The equation now takes the form of substituting the values of angular frequency and phase constant.

x=(4.0cm)cos4蟺t+2蟺3

Therefore the position graph shows two cycles of motion are as follows.

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